Consider the recurrence relation an = 14 an-1 − 56 an-2, n>1, with the initial conditions a0=4, a1=5. The solution of this homogeneous linear recurrence relation of order 2 is of the following form a^(n)=c_(1)r_(1)^(n)+c_(2)r_(2)^(n) for some real numbers r1≠r2 and c1,c2. What is the product c1c2=? Write your answer:
Consider the recurrence relation an = 14 an-1 − 56 an-2, n>1, with the initial conditions a0=4, a1=5. The solution of this homogeneous linear recurrence relation of order 2 is of the following form a^(n)=c_(1)r_(1)^(n)+c_(2)r_(2)^(n) for some real numbers r1≠r2 and c1,c2. What is the product c1c2=? Write your answer:
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Consider the recurrence relation
an = 14 an-1 − 56 an-2, n>1,
with the initial conditions a0=4, a1=5. The solution of this homogeneous linear recurrence relation of order 2 is of the following form
a^(n)=c_(1)r_(1)^(n)+c_(2)r_(2)^(n)
for some real numbers r1≠r2 and c1,c2. What is the product c1c2=? Write your answer:
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