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The solution of the recurrence relation in the problem y"+y=0 about x = 0 (for k = 0, 1, 2, ...) is OaC₂k=co(-1)/(2k + 2)!, C2k+1=C₁(-1)/(2k + 3)! Obc2k=co(-1)/(2k)!, C2k+1=C1(-1)/(2k + 1)! OC2k=co(-1)/(2k-1). C₂k+1=C₁(-1)/(2k)! Odc₂k=co(-1)/(2k), C2k+1=C₁(-1)/(2k + 1) Ocak = co(-1)/(2k)², C2k+1=C₁(-1)/(2k + 1)²

The solution of the recurrence relation in the problem y"+y=0 about x = 0 (for k = 0, 1, 2, ...) is OaC₂k=co(-1)/(2k + 2)!, C2k+1=C₁(-1)/(2k + 3)! Obc2k=co(-1)/(2k)!, C2k+1=C1(-1)/(2k + 1)! OC2k=co(-1)/(2k-1). C₂k+1=C₁(-1)/(2k)! Odc₂k=co(-1)/(2k), C2k+1=C₁(-1)/(2k + 1) Ocak = co(-1)/(2k)², C2k+1=C₁(-1)/(2k + 1)²

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The solution of the recurrence relation in the problem y"+y=0 about x = 0 (for k = 0, 1, 2, ...) is OaC2k=co(-1)/(2k + 2)!. C₂k+1=C₁(-1)/(2k + 3)! Obc2k=co(-1)/(2k)!, C2k+1=C1(-1)/(2k + 1)! OC2k=co(-1)/(2k-1)!, C₂k+1=C₁(-1)/(2k)! Odc₂k=co(-1)/(2k). C₂k+1=C₁(-1)/(2k + 1) Ocak = co(-1)/(2k)², C2k+1=C₁(-1)/(2k + 1)²
Transcribed Image Text:The solution of the recurrence relation in the problem y"+y=0 about x = 0 (for k = 0, 1, 2, ...) is OaC2k=co(-1)/(2k + 2)!. C₂k+1=C₁(-1)/(2k + 3)! Obc2k=co(-1)/(2k)!, C2k+1=C1(-1)/(2k + 1)! OC2k=co(-1)/(2k-1)!, C₂k+1=C₁(-1)/(2k)! Odc₂k=co(-1)/(2k). C₂k+1=C₁(-1)/(2k + 1) Ocak = co(-1)/(2k)², C2k+1=C₁(-1)/(2k + 1)²
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