The closed form solution to the recurrence relation a(n)= a(n-1) + 4 with a(0) = 3 is (A) a(n+1)= a(n) - 3 (B) a(n) = 4 + 3n (C) a(n) = 3 + 4n (D) a(n) = 4n-3 (E) None of the above

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