The closed form solution to the recurrence relation a(n)= a(n-1) + 4 with a(0) = 3 is (A) a(n+1)= a(n) - 3 (B) a(n) = 4 + 3n (C) a(n) = 3 + 4n (D) a(n) = 4n-3 (E) None of the above

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The closed form solution to the recurrence relation a(n) = a(n-1) + 4 with a(0) = 3 is
(A) a (n+1)= a(n) - 3 (B) a(n) = 4 + 3n
(C) a(n) = 3 + 4n
(D) a(n) = 4n-3
(E) None of the above.
Transcribed Image Text:The closed form solution to the recurrence relation a(n) = a(n-1) + 4 with a(0) = 3 is (A) a (n+1)= a(n) - 3 (B) a(n) = 4 + 3n (C) a(n) = 3 + 4n (D) a(n) = 4n-3 (E) None of the above.
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