Consider the reaction: H2(g) + F2(g)2HF(g) Using standard thermodynamic data at 298K, calculate the free energy change when 2.190 moles of H2(g) react at standard conditions. AG° kJ

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**Chemical Reaction Free Energy Calculation**

**Consider the Reaction:**

\[ \text{H}_2(\text{g}) + \text{F}_2(\text{g}) \rightarrow 2\text{HF}(\text{g})\]

**Problem Statement:**

Using standard thermodynamic data at 298K, calculate the free energy change when 2.190 moles of \(\text{H}_2(\text{g})\) react at standard conditions.

**Equation:**

\[ \Delta G^\circ_{\text{rxn}} = \underline{\hspace{3cm}} \text{kJ} \] 

**Instructions:**

To solve this problem, you will need to refer to standard thermodynamic tables for values like the Gibbs free energy of formation (\(\Delta G^\circ_f\)) for each compound at 298K. Calculate the Gibbs free energy change \(\Delta G^\circ_{\text{rxn}}\) for the reaction using the following steps:

1. **Write out the balanced chemical equation for the reaction.**
2. **Find the \(\Delta G^\circ_f\) values for \(\text{H}_2(\text{g})\), \(\text{F}_2(\text{g})\), and \(\text{HF}(\text{g})\).**
3. **Apply the formula to calculate \(\Delta G^\circ_{\text{rxn}}\):**

\[ \Delta G^\circ_{\text{rxn}} = \sum \Delta G^\circ_{f(\text{products})} - \sum \Delta G^\circ_{f(\text{reactants})}\]

4. **After determining \(\Delta G^\circ_{\text{rxn}}\) for 1 mole of \(\text{H}_2(\text{g})\), calculate the total free energy change for 2.190 moles of \(\text{H}_2(\text{g})\).**

\[ \Delta G = \Delta G^\circ_{\text{rxn}} \times 2.190 \text{ moles} \]

**Note:** Fill in the value computed for the free energy change in the provided box.
Transcribed Image Text:**Chemical Reaction Free Energy Calculation** **Consider the Reaction:** \[ \text{H}_2(\text{g}) + \text{F}_2(\text{g}) \rightarrow 2\text{HF}(\text{g})\] **Problem Statement:** Using standard thermodynamic data at 298K, calculate the free energy change when 2.190 moles of \(\text{H}_2(\text{g})\) react at standard conditions. **Equation:** \[ \Delta G^\circ_{\text{rxn}} = \underline{\hspace{3cm}} \text{kJ} \] **Instructions:** To solve this problem, you will need to refer to standard thermodynamic tables for values like the Gibbs free energy of formation (\(\Delta G^\circ_f\)) for each compound at 298K. Calculate the Gibbs free energy change \(\Delta G^\circ_{\text{rxn}}\) for the reaction using the following steps: 1. **Write out the balanced chemical equation for the reaction.** 2. **Find the \(\Delta G^\circ_f\) values for \(\text{H}_2(\text{g})\), \(\text{F}_2(\text{g})\), and \(\text{HF}(\text{g})\).** 3. **Apply the formula to calculate \(\Delta G^\circ_{\text{rxn}}\):** \[ \Delta G^\circ_{\text{rxn}} = \sum \Delta G^\circ_{f(\text{products})} - \sum \Delta G^\circ_{f(\text{reactants})}\] 4. **After determining \(\Delta G^\circ_{\text{rxn}}\) for 1 mole of \(\text{H}_2(\text{g})\), calculate the total free energy change for 2.190 moles of \(\text{H}_2(\text{g})\).** \[ \Delta G = \Delta G^\circ_{\text{rxn}} \times 2.190 \text{ moles} \] **Note:** Fill in the value computed for the free energy change in the provided box.
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