Consider the reaction [CO.H (CO][H2O] K. = 102 %3D (0.125-z)? CO (g) + H2O (g) = CO2 (g) + H2 (g) Ke = 102 at 500 K Since there was no product at the start of the reaction, the final concentration of CO, is equal to 0 + x = x. A reaction mixture initially contains 0.125 M CO and 0.125 M H20. Part D What will be the equilibrium concentration of H2? Express the concentration in molarity to three significant figures. να ΑΣφ (H2) = M

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aland Veterinary.
Free income tax
Bailey Family Foun..
I Review | Constants | Periodic Table
MISSED THIS? Read Section
16.8 (Pages 701 - 710) ; Watch KCV 16.8, IWE
16.9
Equilibrium |0.125 – 1 |0.125
So
Consider the reaction
[CO2][H3]
[CO][H2O]
K.
= 102
(0.125-z)?
CO (g) + H2O (g) = CO2 (g) + H2 (g)
K. = 102 at 500 K
Since there was no product at the start of the reaction, the final concentration of CO2 is equal to
0 + x = x.
A reaction mixture initially contains 0.125 M CO
and 0.125 M H2O.
Part D
What will be the equilibrium concentration of H2?
Express the concentration in molarity to three significant figures.
?
να ΑΣφ
M
(H2] =
Transcribed Image Text:aland Veterinary. Free income tax Bailey Family Foun.. I Review | Constants | Periodic Table MISSED THIS? Read Section 16.8 (Pages 701 - 710) ; Watch KCV 16.8, IWE 16.9 Equilibrium |0.125 – 1 |0.125 So Consider the reaction [CO2][H3] [CO][H2O] K. = 102 (0.125-z)? CO (g) + H2O (g) = CO2 (g) + H2 (g) K. = 102 at 500 K Since there was no product at the start of the reaction, the final concentration of CO2 is equal to 0 + x = x. A reaction mixture initially contains 0.125 M CO and 0.125 M H2O. Part D What will be the equilibrium concentration of H2? Express the concentration in molarity to three significant figures. ? να ΑΣφ M (H2] =
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