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Consider the reaction below to be at equilibrium: 4 Ae) + 3 B(e) + heat - 5 Ce) + 3 Dg) In which direction will the reaction shift if more D is added? It will not shift O It will shift toward the products. O It will shift toward the reactants.

Consider the reaction below to be at equilibrium: 4 Ae) + 3 B(e) + heat - 5 Ce) + 3 Dg) In which direction will the reaction shift if more D is added? It will not shift O It will shift toward the products. O It will shift toward the reactants.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Consider the reaction below to be at equilibrium: 4 A(e) + 3 B(e) + heat 5 Ce) + 3 D(e) In which direction will the reaction shift if more D is added? O It will not shift O It will shift toward the products. O It will shift toward the reactants.
Transcribed Image Text:Consider the reaction below to be at equilibrium: 4 A(e) + 3 B(e) + heat 5 Ce) + 3 D(e) In which direction will the reaction shift if more D is added? O It will not shift O It will shift toward the products. O It will shift toward the reactants.
Expert Solution
Step 1

 The given reaction is:

4A(g)+3B(g)+heat  ⇔  5C(g)+3D(g)

The given reaction is in equilibrium:

Thus, from the law of mass action, for a reaction aA+bB ⇔cC+dD; the equilibrium constant K is given as follows:

K=[C]c[D]d[A]a[B]b

i.e.K=[Products]n[Reactants]m               (equation 1)

For the given reaction, K is;

K=[C]5[D]3[A]4[B]3

 

 

 

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