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The free energy change for the following reaction at 25 °C, when [Co²+] = 1.15 M and [Cd²+] = 6.07x10-³ M, is -36.7 kJ: Co²+(1.15 M) + Cd(s) Co(s) + Cd²+(6.07x10-³ M) AG = -36.7 kJ What is the cell potential for the reaction as written under these conditions? Answer: Would this reaction be spontaneous in the forward or the reverse direction? [forward

The free energy change for the following reaction at 25 °C, when [Co²+] = 1.15 M and [Cd²+] = 6.07x10-³ M, is -36.7 kJ: Co²+(1.15 M) + Cd(s) Co(s) + Cd²+(6.07x10-³ M) AG = -36.7 kJ What is the cell potential for the reaction as written under these conditions? Answer: Would this reaction be spontaneous in the forward or the reverse direction? [forward

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The free energy change for the following reaction at 25 °C, when [Co²+] = 1.15 M and [Cd²+] = 6.07×10 3 M, is -36.7 kJ: Co²+(1.15 M) + Cd(s)— Co(s) + Cd²+(6.07×10-³ M) AG = -36.7 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction? forward ✓
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [Co²+] = 1.15 M and [Cd²+] = 6.07×10 3 M, is -36.7 kJ: Co²+(1.15 M) + Cd(s)— Co(s) + Cd²+(6.07×10-³ M) AG = -36.7 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction? forward ✓
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