Consider the reaction: 2HBr(g) → H₂(g) + Br₂ (1) Using standard absolute entropies at 298 K, calculate the entropy change for the system when 2.01 moles of HBr (g) react at standard conditions. ASO Substance So system H₂(g) Br₂ (1) HBr(g) = J K.mol 130.7 152.2 198.7 J/K

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**Entropy Change Calculation for a Chemical Reaction**

Consider the reaction:

\[ 2\text{HBr(g)} \rightarrow \text{H}_2\text{(g)} + \text{Br}_2\text{(l)} \]

Using standard absolute entropies at 298 K, calculate the entropy change for the system when 2.01 moles of \(\text{HBr(g)}\) react at standard conditions.

**Table of Standard Entropies:**

| Substance | \( S^\circ \) (J/K·mol) |
|-----------|---------------------|
| \(\text{H}_2\text{(g)}\)   | 130.7              |
| \(\text{Br}_2\text{(l)}\)  | 152.2              |
| \(\text{HBr(g)}\)          | 198.7              |

**Calculate \(\Delta S^\circ_{\text{system}}\):**

\[ \Delta S^\circ_{\text{system}} = \text{[Insert Calculation Here]} \, \text{J/K} \]

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Transcribed Image Text:**Entropy Change Calculation for a Chemical Reaction** Consider the reaction: \[ 2\text{HBr(g)} \rightarrow \text{H}_2\text{(g)} + \text{Br}_2\text{(l)} \] Using standard absolute entropies at 298 K, calculate the entropy change for the system when 2.01 moles of \(\text{HBr(g)}\) react at standard conditions. **Table of Standard Entropies:** | Substance | \( S^\circ \) (J/K·mol) | |-----------|---------------------| | \(\text{H}_2\text{(g)}\) | 130.7 | | \(\text{Br}_2\text{(l)}\) | 152.2 | | \(\text{HBr(g)}\) | 198.7 | **Calculate \(\Delta S^\circ_{\text{system}}\):** \[ \Delta S^\circ_{\text{system}} = \text{[Insert Calculation Here]} \, \text{J/K} \] **Buttons:** - **Submit Answer** - **Retry Entire Group** **Attempts Remaining:** 9 more group attempts remaining. **Navigation:** - **Previous** - **Next**
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