Consider the production data shown in this example. (Assume a normal distribution. Due to the nature of this problem, (a) What is the mean (in minutes)? x = 9.22 minutes (b) What is the standard deviation (in minutes)? 515.16 S Z 99 X-X S 2.2811 (c) Determine the z value corresponding to a 5-minute-assembly time. 59.22 2.2811 minutes -1.85

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EXAMPLE
In order to improve the production time, the supervisor of assembly lines
for a computer manufacturer has studied the time that it takes to assem-
ble certain parts of a computer at various stations. She measures the time
that it takes to assemble a specific part by 100 people at different shifts
and on different days. The record of her study is organized and shown
in the table below.
Based on data provided, we have calculated the probabilities correspond-
ing to the time intervals that people took to assemble the parts. The
probability distribution for this example is shown in the table below and
the following figure.
Data Pertaining to this example
Time That It Takes a Person to
Assemble the Part (minutes)
5
Probability
0.18
0.16
0.14
0.12
0.10
0.08
0.06
0.04
0.02
0.00
6
5 6
7
8
9
10
AWN ==
11
12
13
14
Frequency
5
8
11
15
17
14
13
8
6
3
Σ=100
Again, note that the sum of probabilities is equal to 1. Also note that
if we were to connect the midpoints of time results (as shown in the figure
below), we would have a curve that approximates a bell shape. As the
number of data points increases and the intervals decrease, the
probability-distribution curve becomes smoother. A probability
distribution that has a bell-shaped curve is called a normal distribution.
The probability distribution for many engineering experiments is
approximated by a normal distribution.
7 8 9 10 11 12 13 14
Time (minutes)
Plot of probability distribution for this example.
Probability
(P)
0.05
0.08
0.11
0.15
0.17
0.14
0.13
0.08
0.06
0.03
Σp=1
Transcribed Image Text:EXAMPLE In order to improve the production time, the supervisor of assembly lines for a computer manufacturer has studied the time that it takes to assem- ble certain parts of a computer at various stations. She measures the time that it takes to assemble a specific part by 100 people at different shifts and on different days. The record of her study is organized and shown in the table below. Based on data provided, we have calculated the probabilities correspond- ing to the time intervals that people took to assemble the parts. The probability distribution for this example is shown in the table below and the following figure. Data Pertaining to this example Time That It Takes a Person to Assemble the Part (minutes) 5 Probability 0.18 0.16 0.14 0.12 0.10 0.08 0.06 0.04 0.02 0.00 6 5 6 7 8 9 10 AWN == 11 12 13 14 Frequency 5 8 11 15 17 14 13 8 6 3 Σ=100 Again, note that the sum of probabilities is equal to 1. Also note that if we were to connect the midpoints of time results (as shown in the figure below), we would have a curve that approximates a bell shape. As the number of data points increases and the intervals decrease, the probability-distribution curve becomes smoother. A probability distribution that has a bell-shaped curve is called a normal distribution. The probability distribution for many engineering experiments is approximated by a normal distribution. 7 8 9 10 11 12 13 14 Time (minutes) Plot of probability distribution for this example. Probability (P) 0.05 0.08 0.11 0.15 0.17 0.14 0.13 0.08 0.06 0.03 Σp=1
Consider the production data shown in this example. (Assume a normal distribution. Due to the nature of this problem,
(a) What is the mean (in minutes)?
x = 9.22
minutes
(b) What is the standard deviation (in minutes)?
515.16
S =
Z =
X-X
S
99
(c) Determine the z value corresponding to a 5-minute-assembly time.
5- 9.22
= -1.85
2.2811
=
2.2811
minutes
(d) Referring to this table, determine the A value.
A =
(e) Determine the probability that it will take a person longer than 5 minutes to assemble the computer parts.
0.5 +
Transcribed Image Text:Consider the production data shown in this example. (Assume a normal distribution. Due to the nature of this problem, (a) What is the mean (in minutes)? x = 9.22 minutes (b) What is the standard deviation (in minutes)? 515.16 S = Z = X-X S 99 (c) Determine the z value corresponding to a 5-minute-assembly time. 5- 9.22 = -1.85 2.2811 = 2.2811 minutes (d) Referring to this table, determine the A value. A = (e) Determine the probability that it will take a person longer than 5 minutes to assemble the computer parts. 0.5 +
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