Consider the population of commuting time to school for all John Jay College students during Spring 2022. The commuting times have a mean of 95 minutes and a standard deviation of 22 minutes. One student from STA 250-99 class had a commuting time of 2 hours and 15 minutes. What is the z score for this commuting time? (Give your answer correct to two decimal places.)
Consider the population of commuting time to school for all John Jay College students during Spring 2022. The commuting times have a mean of 95 minutes and a standard deviation of 22 minutes. One student from STA 250-99 class had a commuting time of 2 hours and 15 minutes. What is the z score for this commuting time? (Give your answer correct to two decimal places.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Understanding Z-Scores with Commuting Times**
Consider the population of commuting time to school for all John Jay College students during Spring 2022. The commuting times have a mean of 95 minutes and a standard deviation of 22 minutes. One student from STA 250-99 class had a commuting time of 2 hours and 15 minutes. What is the z score for this commuting time? (Give your answer correct to two decimal places.)
---
### Analysis and Explanation:
#### Definitions:
1. **Mean (μ):** The average value of all the commuting times, which is 95 minutes.
2. **Standard Deviation (σ):** A measure of how spread out the numbers are, which is 22 minutes.
3. **Z-Score:** The number of standard deviations a data point is from the mean.
#### Calculation Steps:
1. **Convert the commuting time to minutes**:
- 2 hours and 15 minutes = 2 * 60 + 15 = 120 + 15 = 135 minutes.
2. **Apply the Z-Score formula**:
\[
Z = \frac{(X - \mu)}{\sigma}
\]
Where:
- \( X \) = observed value (135 minutes)
- \( \mu \) = mean (95 minutes)
- \( \sigma \) = standard deviation (22 minutes)
3. **Substitute the values**:
\[
Z = \frac{(135 - 95)}{22}
\]
4. **Calculate the Z-Score**:
\[
Z = \frac{40}{22} \approx 1.82
\]
#### Conclusion:
The z score for the student's commuting time is approximately 1.82. This means the student's commuting time is 1.82 standard deviations above the mean commuting time.
---
**Note:** Z-Scores allow us to understand how a particular value compares to the overall distribution of the data. In this case, the student's commuting time is significantly above average.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7f54fed8-fa4e-41a3-be1d-05f34a1734d9%2F9080a7c3-e2e0-4226-bbc5-5026d347e7a0%2F182e2gy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Understanding Z-Scores with Commuting Times**
Consider the population of commuting time to school for all John Jay College students during Spring 2022. The commuting times have a mean of 95 minutes and a standard deviation of 22 minutes. One student from STA 250-99 class had a commuting time of 2 hours and 15 minutes. What is the z score for this commuting time? (Give your answer correct to two decimal places.)
---
### Analysis and Explanation:
#### Definitions:
1. **Mean (μ):** The average value of all the commuting times, which is 95 minutes.
2. **Standard Deviation (σ):** A measure of how spread out the numbers are, which is 22 minutes.
3. **Z-Score:** The number of standard deviations a data point is from the mean.
#### Calculation Steps:
1. **Convert the commuting time to minutes**:
- 2 hours and 15 minutes = 2 * 60 + 15 = 120 + 15 = 135 minutes.
2. **Apply the Z-Score formula**:
\[
Z = \frac{(X - \mu)}{\sigma}
\]
Where:
- \( X \) = observed value (135 minutes)
- \( \mu \) = mean (95 minutes)
- \( \sigma \) = standard deviation (22 minutes)
3. **Substitute the values**:
\[
Z = \frac{(135 - 95)}{22}
\]
4. **Calculate the Z-Score**:
\[
Z = \frac{40}{22} \approx 1.82
\]
#### Conclusion:
The z score for the student's commuting time is approximately 1.82. This means the student's commuting time is 1.82 standard deviations above the mean commuting time.
---
**Note:** Z-Scores allow us to understand how a particular value compares to the overall distribution of the data. In this case, the student's commuting time is significantly above average.
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