Consider the particle with the small positive charge located at some distance from a positively charged sphere in Figure 22.24b. If you push the particle closer to the sphere, you will expend energy to overcome electrical repulsion; that is, you will do work in pushing the charged particle against the electric field of the sphere. This work done in moving the particle to its new location increases its energy. We call the energy the particle possesses by virtue of its location, electric potential energy. If the particle is released, it accelerates in a direction away from the sphere, and its electric potential energy changes to kinetic energy. FIGURE 22.24 What will happen to the electrical potential energy and work If we instead push a particle with twice the charge? Calculate the electric potential energy and work, given that the radial distance between two charges at point A is 0.150 meters and point B is 0.110 meters. The sphere (q) has a charge of +4.30 X 10* Coulomb.
Consider the particle with the small positive charge located at some distance from a positively charged sphere in Figure 22.24b. If you push the particle closer to the sphere, you will expend energy to overcome electrical repulsion; that is, you will do work in pushing the charged particle against the electric field of the sphere. This work done in moving the particle to its new location increases its energy. We call the energy the particle possesses by virtue of its location, electric potential energy. If the particle is released, it accelerates in a direction away from the sphere, and its electric potential energy changes to kinetic energy. FIGURE 22.24 What will happen to the electrical potential energy and work If we instead push a particle with twice the charge? Calculate the electric potential energy and work, given that the radial distance between two charges at point A is 0.150 meters and point B is 0.110 meters. The sphere (q) has a charge of +4.30 X 10* Coulomb.
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Transcribed Image Text:Consider the particle with the small positive charge
located at some distance from a positively charged sphere in
Figure 22.24b. If you push the particle closer to the sphere,
you will expend energy to overcome electrical repulsion; that
is, you will do work in pushing the charged particle against
the electric field of the sphere. This work done in moving the
particle to its new location increases its energy. We call the
energy the particle possesses by virtue of its location,
electric potential energy. If the particle is released, it
accelerates in a direction away from the sphere, and its
electric potential energy changes to kinetic energy.
FIGURE 22.24
What will happen to the electrical potential energy and work If we instead push a
particle with twice the charge?
Calculate the electric potential energy and work, given that the radial distance
between two charges at point A is 0.150 meters and point B is 0.110 meters. The sphere
(q) has a charge of +4.30 X 10* Coulomb.
Charge, q.
(C,
Coulomb)
Electric Potential Energy,
EPE
Work ((J,
EPE + Charge = U/q,
(V, Volts)
Joule)
(J, Joule)
UA:
Us:
AU
(using U.) (using Us)
Using AU
2.40 X 10*
UA:
Us:
AU
4.80 X 10
Ug:
AU
9.6 X 10*
Equations:
U, = k q, q/r.
U. = k q, q/r.
W = -AU = -(U, - U) = U, - U,
„U = U. - U,
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