Consider the motion of a particle in two dimensions given by the Lagrangian m L= x+ where i>0. The initial conditions are given as y(0) = 0, x(0) = 42 meters, *(0) = j(0) = 0. What is the value of x(t)– y(t) at t = 25 seconds in meters?
Consider the motion of a particle in two dimensions given by the Lagrangian m L= x+ where i>0. The initial conditions are given as y(0) = 0, x(0) = 42 meters, *(0) = j(0) = 0. What is the value of x(t)– y(t) at t = 25 seconds in meters?
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Transcribed Image Text:Consider the motion of a particle in two dimensions given by the Lagrangian
m
L =
2
(x+
where i>0 . The initial conditions are given as y(0)=0, x(0) = 42 meters,
*(0) = y (0) = 0. What is the value of x(t)– y(t) at t= 25 seconds in meters?
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