Problem 4: Arunner runs around a circular track. He completes one lap at a time of t= 386 s at a constant speed of v = 4.7 m/s.Randomized Variablest = 386 sv = 4.7 m/sWhat is the radius, r in meters, of the track?a()7 8 9E A 4 52 3sin()cos()tan()HOMEcotan()asin()acos()6atan()acotan()sinh()1cosh()tanh()cotanh()ENDO Degrees O RadiansVOl BACKSPACEDELCLEARSubmitI give up!HintFeedbackWhat was the runners centripetal acceleration, a, in m/s, during the run?

Answered: Problem 4: Arunner runs around a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Problem 4: The center of a moon of mass m= 2 x 1023 kg is a distance D = 28 × 10° km from the center of a planet of mass M = 19.9 × 1023 kg. At some distance x from the center of the planet, along a line connecting the centers of planet and moon, the net force on an object will be zero.
During service, a tennis ball is struck at height h = 1.95 m above a tennis court and moves with velocity v0 = v0xi. Assume the ball encounters no air resistance, and use a Cartesian coordinate system with the origin located at the ball's initial position.Randomized Variablesh = 1.95 mv0x = 25.5 m/s Calculate the tennis ball’s horizontal velocity, vfx in m/s, when it strikes the court?
Problem 7: During service, a tennis ball is struck at height h = 1.95 m above a tennis court and moves with velocity vo = voi. Assume the ball encounters no air resistance, and use a Cartesian coordinate system with the origin located at the ball's initial position. Randomized Variables h = 1.95 m Vor = 23.5 m/s
Problem 13: In this problem, the symbols M, L, and T represent the dimensions mass, length, and time, respectively. Consider the physical quantities s, v, a, and t with dimensions [s] = L, [v] = LT-1, [a] = LT-2, and [t] = T. (Here, the square bracket means “the dimensions of” so, for example, [s] represents the dimensions of the quantity s.) Part (a) What is the simplest expression involving only a and s that has the same dimensions as v2? expression = ______ Part (b) What is the simplest expression involving only v and t that has the same dimensions as a? expression = ______ Part (c) What is the simplest expression involving only v and t that has the same dimensions as s? expression = ______ Part (d) What is the simplest expression involving only a and t that has the same dimensions as s? expression = ______
I1:00:00 PM Problem 3: Suppose the speed of light were only 3000.0 m's. A jet fighter moving toward a target on the ground at 810 m/s shoots bullets, each having a muzzle velocity of 1050 m's. Randomized Variables v-810 m/s v2 1050 m's ed What is the velocity of the bullets relative to the target in km's? Grade Sommary Deductions 0% Potential 100%
Bob has just finished climbing a sheer cliff above a beach, and wants to figure out how high he climbed. All he has to use, however, is a baseball, a stopwatch, and a friend on the beach below with a long measuring tape. Bob is a pitcher and he knows that the fastest he can throw the ball is about ?0=34.1 m/s. Bob starts the stopwatch as he throws the ball (with no way to measure the ball's initial trajectory), and watches carefully. The ball rises and then falls, and after ?1=0.510 s the ball is once again level with Bob. Bob cannot see well enough to the time when the ball hits the ground. Bob's friend then measures that the ball landed ?=126 m from the base of the cliff. How high up is Bob, if the ball started exactly 2 m above the edge of the cliff?
A rectangle expands and contracts with time t (in seconds). Its area is given by A= 4 + sin t square meters. At t = 3.14 (pi), the following is observed. (1) the width of the rectangle expands at the rate of 0.1 meters per second. (2) The width of the rectangle is 1 meter long How fast is the height of the rectangle changing at t = 3.14 (pi)?
This time the quantities will be different, again randomly chosen by the computer. The mass will be much smaller for a different reason. The shell is thin, but has a definite thickness. Calculate the (volume) density of the shell, in g/cm3. Here are the numbers: R = 27 cm M = 800 grams thickness = 0.4 mm
The density of platinum is 21.45 x 103 kg/m3. a. Calculate the volume (in m3/atom) occupied per platinum atom b. Estimate the atomic diameter (in m);(The estimate uses the approximation that it is a cubic volume) c. Using this estimation, calculate the thickness of a metal foil (in m) containing 2.0 x 101 atomic layers of platinum.
A relationship is found between the number density of cars on a freeway during rush hour, N, and distance. The relationship can be written as k a'N No dr? From this you can conclude that O w = V No O v = No No O v =

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