Consider the molecule trans-1-ethyl-2-methylcyclohexane. What can you say about the most stable form of this molecule? The ethyl is axial and the methyl is equatorial The methyl is axial and the ethyl is equatorial Both substituents are axial Both substituents are equatorial

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### Analysis of the Most Stable Form of Trans-1-ethyl-2-methylcyclohexane

**Question:**
Consider the molecule **trans-1-ethyl-2-methylcyclohexane**.

**What can you say about the _most stable_ form of this molecule?**

**Options:**
1. The ethyl is axial and the methyl is equatorial.
2. The methyl is axial and the ethyl is equatorial.
3. Both substituents are axial.
4. Both substituents are equatorial.

### Explanation of Stability

In cyclohexane chair conformations:

- **Axial positions** are aligned perpendicular to the plane of the ring, alternating up and down along the ring structure.
- **Equatorial positions** are aligned roughly parallel to the plane of the ring and extend outward from the ring, alternating slightly above and below the plane.

Substituents prefer to occupy the equatorial position due to reduced 1,3-diaxial interactions (steric hindrance). 

For **trans-1-ethyl-2-methylcyclohexane**:

- Each substituent prefers the equatorial position to minimize steric strain.
- In the trans configuration, the substituents lie on opposite sides of the cyclohexane ring.

**Most Stable Form:**
To achieve minimal steric hindrance and maximize stability, the correct answer would be:

4. Both substituents are equatorial. (minimizing steric interactions)

**Note:**
A diagram or model would significantly enhance the understanding of the spatial orientation and confirm that both substituents being equatorial reduces potential strain the most effectively.
Transcribed Image Text:### Analysis of the Most Stable Form of Trans-1-ethyl-2-methylcyclohexane **Question:** Consider the molecule **trans-1-ethyl-2-methylcyclohexane**. **What can you say about the _most stable_ form of this molecule?** **Options:** 1. The ethyl is axial and the methyl is equatorial. 2. The methyl is axial and the ethyl is equatorial. 3. Both substituents are axial. 4. Both substituents are equatorial. ### Explanation of Stability In cyclohexane chair conformations: - **Axial positions** are aligned perpendicular to the plane of the ring, alternating up and down along the ring structure. - **Equatorial positions** are aligned roughly parallel to the plane of the ring and extend outward from the ring, alternating slightly above and below the plane. Substituents prefer to occupy the equatorial position due to reduced 1,3-diaxial interactions (steric hindrance). For **trans-1-ethyl-2-methylcyclohexane**: - Each substituent prefers the equatorial position to minimize steric strain. - In the trans configuration, the substituents lie on opposite sides of the cyclohexane ring. **Most Stable Form:** To achieve minimal steric hindrance and maximize stability, the correct answer would be: 4. Both substituents are equatorial. (minimizing steric interactions) **Note:** A diagram or model would significantly enhance the understanding of the spatial orientation and confirm that both substituents being equatorial reduces potential strain the most effectively.
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