Consider the LP with n variables and 2n linear constraints, henceforth de-noted CUBER:maxS = xn-10x110x1 ≤ 9-1-xi 10x+1 ≤ 0i = 1,...,n-1Ꮖ 1, .xi+10x+1 ≤ 10 i = 1,..., n − 1,...,xn≥0a) (No written answer to this question is required.) Let n = 4. Introduceslack variables w₁,..., wg and an artificial variable xo representing con-straint tolerance. Apply the online pivot toolhttps://vanderbei.princeton.edu/JAVA/pivot/simple.html in order tofind a feasible solution to CUBE by means of Phase 1 of the Sim-plex algorithm. Verify that the dictionary after Phase 1 (the column corresponding to x deleted and restored in row 0) is:10000+ 10000 + 1000 W3 + 110 5 + 171S =1x1=-10աշ=x2=-100W4=9549-1x3-=1000W6=49950-1=W8=100004999500--10015-11000-1W1W1w₁W110000 W11500 W₁-W3-----1511000W3W3w3W3W3----wsW5TW5100 W515w5--W7W7

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Answered: Consider the LP with n variables and 2n…

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