Theorem 4.1. The positive equilibrium point Eo of system (4) is not asymptotically stable and nonhyperbolic point . Proof. The linearized system of (4) evaluated at Eo is written in the matrix form as Ln+1 = Q Ln,

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Theorem 4.1. The positive equilibrium point E, of system (4) is not asymptotically stable
and nonhyperbolic point .
Proof. The linearized system of (4) evaluated at Eo is written in the matrix form as
Ln+1
Q Ln
where Ln
(Wn, Zn, Wn-1, Zn–1, Wn-2, zn-2)' and the Jacobian matrix determined at Eo is equal
-2
e-1
-(e²+2e-3)
-(4 µ)
(e?+2 e-3)
e+3
e+3
-(e+3)
2 µ
-(e+3)
1-e
2
(28)
1
1
1
9.
Transcribed Image Text:Theorem 4.1. The positive equilibrium point E, of system (4) is not asymptotically stable and nonhyperbolic point . Proof. The linearized system of (4) evaluated at Eo is written in the matrix form as Ln+1 Q Ln where Ln (Wn, Zn, Wn-1, Zn–1, Wn-2, zn-2)' and the Jacobian matrix determined at Eo is equal -2 e-1 -(e²+2e-3) -(4 µ) (e?+2 e-3) e+3 e+3 -(e+3) 2 µ -(e+3) 1-e 2 (28) 1 1 1 9.
In this paper, we solve and study the properties of the following system
Wn-p 2 Zn-h
p=0
Wn-p
h=0
E zn-h
h=1
p=1
Wn+1
+u and zn+1 =
+e,
(4)
Zn - €
Wn - 4
where u and e are arbitrary positive real numbers with initial conditions w; and z; for i =
-2, –1,0.
Theorem 2.1. Let {wn, z„}-2 be a solution of (4), then
6+ V – 4 ko k1
A
- V2 – 4 ko ki
1- ki + ko
+
w2n-2
+B
Ty – Oy -
- V2 - 4 ko ki
-4 ko ki
+ V2 – 4 ko ki
V2 - 4 ko ki
A
ko
+ B
ko
w2n-1
- 1
2
2
•((금-1) (는)
1– ko + k1
+ V2 - 4 vo V1
- V2 - 4 VI
1- v + vo
22n-2
+D
%3D
1
+ Vu2 – 4 o VI
gb + V2 – 4 vo vỊ
1
1.
+D
- V2 – 4 v vỊ
V2 – 4 vo vi
22n-1
- v + vo
1- 0 - VI
where A, B, C and D are constants defined as
wo -H
2-1 +z-2
ko
ki =
0 = ko + ki + ko ki,
w-1 + w-2
20 - e
20 - e
w-1 +w-2
, = vo + vi + vo V1,
2-1 +2-2
1-Om
Vo2 – 4 ko k1
-)") (v - 4ko ki – 4) + 2 (wo - (G ) -).
2 62 - 8 ko ki
V2- 4 ko ki
262 - 8 ko ki
1- ko + ki
- ko – k1
(1 – kj + ko
1- k1 - ko
B =
u- w-2
+2
wn-
- vi +u
C =
-2
+ 2
22 - 8 0 vI
- o - VI
) [(는
1- v1 + o
- v0 - v1
1- v + o
2) (V2 – 4vo vI +
+2
2 2
-- 0 - v1
since ko + ki #1 and vo + vı #1 for n e N.
Proof. To obtain the expressions of the general solutions for (4), we rewrite it in the follow
form
2 zn-h
Wn-p
p=1
Wn+1
h=1
Zn+1
and
(5)
1
E Wn-p
1
> Zn-h
h=0
wn -u
p-0
4
Then, we assume that
Wn+1 - l
Wn - H
kn+1 =
1
kn =
2
Wn-p
p=0
Wn-p
p=1
(6)
Zn+1 -€
Zn - €
Vn+1 =
Vn
2
E Zn-h
> Zn-h
h=1
h=0
Substituting (6) in (5), we have
Zn-h
h=1
1
== kn-1,
Vn
kn+1 =
(7)
E Wn-p
p=1
Vn+1 =
= Vn-1.
kn
%3D
Wn -
Hence, we see that
1
ki = -,
Vo
wo - H
20 - €
ko
w-1+ w_2
Vo =
Z-1+ z-2
ko
and
at n = 1, k2 = ko and
V2 = Vo,
at n = 2, k3 = k1 and
V3 = V1,
at n = 3, k4 = ko and
V4 = Vo,
at n = 4, ks = k and
V5 = V1,
(8)
at n = 2 n, k2n = ko and
V2n = Vo,
at n = 2n + 1, k2n+1 = k, and
V2n+1 = V1.
Now, from the relations in (6) we get
Wn = µ+ kn (wn-1 + wn-2) and zn = e + vn (žn-1 + zn-2).
(9)
Using (8) in (9), we have
W2n = H+ ko (w2n-1 + w2n-2),
W2n+1 = µ+ k1 (w2n + w2n-1),
(10)
Z2n = €+ vo (z2n-1 + 2n-2),
22n+1 = €+ V1 (22n + 22n-1).
Transcribed Image Text:In this paper, we solve and study the properties of the following system Wn-p 2 Zn-h p=0 Wn-p h=0 E zn-h h=1 p=1 Wn+1 +u and zn+1 = +e, (4) Zn - € Wn - 4 where u and e are arbitrary positive real numbers with initial conditions w; and z; for i = -2, –1,0. Theorem 2.1. Let {wn, z„}-2 be a solution of (4), then 6+ V – 4 ko k1 A - V2 – 4 ko ki 1- ki + ko + w2n-2 +B Ty – Oy - - V2 - 4 ko ki -4 ko ki + V2 – 4 ko ki V2 - 4 ko ki A ko + B ko w2n-1 - 1 2 2 •((금-1) (는) 1– ko + k1 + V2 - 4 vo V1 - V2 - 4 VI 1- v + vo 22n-2 +D %3D 1 + Vu2 – 4 o VI gb + V2 – 4 vo vỊ 1 1. +D - V2 – 4 v vỊ V2 – 4 vo vi 22n-1 - v + vo 1- 0 - VI where A, B, C and D are constants defined as wo -H 2-1 +z-2 ko ki = 0 = ko + ki + ko ki, w-1 + w-2 20 - e 20 - e w-1 +w-2 , = vo + vi + vo V1, 2-1 +2-2 1-Om Vo2 – 4 ko k1 -)") (v - 4ko ki – 4) + 2 (wo - (G ) -). 2 62 - 8 ko ki V2- 4 ko ki 262 - 8 ko ki 1- ko + ki - ko – k1 (1 – kj + ko 1- k1 - ko B = u- w-2 +2 wn- - vi +u C = -2 + 2 22 - 8 0 vI - o - VI ) [(는 1- v1 + o - v0 - v1 1- v + o 2) (V2 – 4vo vI + +2 2 2 -- 0 - v1 since ko + ki #1 and vo + vı #1 for n e N. Proof. To obtain the expressions of the general solutions for (4), we rewrite it in the follow form 2 zn-h Wn-p p=1 Wn+1 h=1 Zn+1 and (5) 1 E Wn-p 1 > Zn-h h=0 wn -u p-0 4 Then, we assume that Wn+1 - l Wn - H kn+1 = 1 kn = 2 Wn-p p=0 Wn-p p=1 (6) Zn+1 -€ Zn - € Vn+1 = Vn 2 E Zn-h > Zn-h h=1 h=0 Substituting (6) in (5), we have Zn-h h=1 1 == kn-1, Vn kn+1 = (7) E Wn-p p=1 Vn+1 = = Vn-1. kn %3D Wn - Hence, we see that 1 ki = -, Vo wo - H 20 - € ko w-1+ w_2 Vo = Z-1+ z-2 ko and at n = 1, k2 = ko and V2 = Vo, at n = 2, k3 = k1 and V3 = V1, at n = 3, k4 = ko and V4 = Vo, at n = 4, ks = k and V5 = V1, (8) at n = 2 n, k2n = ko and V2n = Vo, at n = 2n + 1, k2n+1 = k, and V2n+1 = V1. Now, from the relations in (6) we get Wn = µ+ kn (wn-1 + wn-2) and zn = e + vn (žn-1 + zn-2). (9) Using (8) in (9), we have W2n = H+ ko (w2n-1 + w2n-2), W2n+1 = µ+ k1 (w2n + w2n-1), (10) Z2n = €+ vo (z2n-1 + 2n-2), 22n+1 = €+ V1 (22n + 22n-1).
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