Consider the given graphs: Ug 117 14₂ 116 11₂ 115 113 14 Vs V7 V6 1/₂ V5 V3 G H Click and drag the statements in correct order either to show that these graphs are not isomorphic or to find an isomorphism between them using paths. Proceeding along similar lines, complete the bijection with us →→ V8, U6 V7, and u7 → Vs. Having thus been led to the only possible isomorphism, check that the 12 edges of G exactly correspond to the 12 edges of H, and the two graphs are isomorphic. Now u, is adjacent to uz and us, and v2 is adjacent to vi and v), so u₂v and us v₁. Having thus been led to the only possible isomorphism, check that the 12 edges of G do not correspond to the 12 edges of H; hence the two graphs are not isomorphic. Since u4 is the other vertex adjacent to us and v4 is the other vertex adjacent to V3, U4 V4. So try to construct an isomorphism that matches them, say U₁ V2 and Us → V6.
Consider the given graphs: Ug 117 14₂ 116 11₂ 115 113 14 Vs V7 V6 1/₂ V5 V3 G H Click and drag the statements in correct order either to show that these graphs are not isomorphic or to find an isomorphism between them using paths. Proceeding along similar lines, complete the bijection with us →→ V8, U6 V7, and u7 → Vs. Having thus been led to the only possible isomorphism, check that the 12 edges of G exactly correspond to the 12 edges of H, and the two graphs are isomorphic. Now u, is adjacent to uz and us, and v2 is adjacent to vi and v), so u₂v and us v₁. Having thus been led to the only possible isomorphism, check that the 12 edges of G do not correspond to the 12 edges of H; hence the two graphs are not isomorphic. Since u4 is the other vertex adjacent to us and v4 is the other vertex adjacent to V3, U4 V4. So try to construct an isomorphism that matches them, say U₁ V2 and Us → V6.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Consider the given graphs:
U18
u₂
16
15
●113
14
Vg
V7
V₁
V6
V/₂
V5
V3
V4
G
H
Click and drag the statements in correct order either to show that these graphs are not isomorphic or to find an isomorphism between
them using paths.
Proceeding along similar lines, complete the bijection with us → V8, U6 → V7,
and U7 → VS.
Having thus been led to the only possible isomorphism, check that the 12 edges of G
exactly correspond to the 12 edges of H, and the two graphs are isomorphic.
Now u, is adjacent to uz and us, and v₂ is adjacent to v₁ and vi, so u₂<> v. and us > V
Having thus been led to the only possible isomorphism, check that the 12 edges of G
do not correspond to the 12 edges of H; hence the two graphs are not isomorphic.
Since u4 is the other vertex adjacent to us and v4 is the other vertex adjacent to
V3, U4 → V4.
So try to construct an isomorphism that matches them, say u₁ → V₂ and Us → V6.
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