Promesile 4 Discussion XlabпетрModule 4 Discussion X17290/assignments/18852997► Q 10 (0/10)rade: 50/100rint VersionWhat is Antireflexive (or irreflexive)?Module 4 DiscussionConsider the relation S on set (a, b, c} given byS = {(a, a),(a, b), (b, a), (b, b), (c, c), (b, c), (c, b)}Prove S is reflexive.Prove S is symmetric.Show S is not an equivalence relation.MacBook ProtvMon 8:1Module 4 DiscussionW

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Answered: Module 4 Discussion X Module 4…

Advanced Engineering Mathematics

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Author:Erwin Kreyszig

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Chapter2: Second-order Linear Odes

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Let A = {a, b, c, d, and let R be the relation R = {(a, a), (b, b), (c, c), (d, d), (c, b), (a, d), (b, a), (b, d), (c, d), (c, a)}. Is R a total order on A? Yes No Justify your answer. (Select all that apply.) R is antisymmetric. R is not antisymmetric. There exists a chain in R that contains every element of A. There does not exist a chain in R that contains every element of A. R is transitive. R is not transitive. Each element of A exists in R. Each element of A does not exist in R. R is reflexive. R is not reflexive.
4- The orthogonal relation is A: symmetric and reflective relation B: symmetric and not reflective relation C: reflective and not symmetric relation O A O B Ос
Let A = (0,1,2,3). The relations R, S and T in the set A are defined as follows…R={(0,0),(0,1),(0,3),(1,0),(1,1),(1,3),(2,2),(3,0),(3,1),(3,3)}S ={(0,0),(0,2),(0,3),(2,3)}T={(0,1),(2,3)}Find the equivalent relation is:
Discrete math: please provide me 100% accurate answers
Let A = {3, 5, 6}, R relation on A defined by R = {(a, b) : a > b, a, b E A}. Write R. O a. {(3,5), (3,6), (5,6)} O b. {(3,5), (3,6)} O C {(5,3), (6,3), (6,5)} O d. {(5,3), (6,3)}
Theorem: Let R ⊆ A × A be a relation. Then R is transitive if and only if R ◦ R ⊆ R. Prove Theorem: show that R is transitive if and only if R ◦ R ⊆ R. No handwritten please
Define relations R 1 , … , R 6 on { 1 , 2 , 3 , 4 } by R 1 = { ( 2 , 2 ) , ( 2 , 3 ) , ( 2 , 4 ) , ( 3 , 2 ) , ( 3 , 3 ) , ( 3 , 4 ) } , R 2 = { ( 1 , 1 ) , ( 1 , 2 ) , ( 2 , 1 ) , ( 2 , 2 ) , ( 3 , 3 ) , ( 4 , 4 ) } , R 3 = { ( 2 , 4 ) , ( 4 , 2 ) } , R 4 = { ( 1 , 2 ) , ( 2 , 3 ) , ( 3 , 4 ) } , R 5 = { ( 1 , 1 ) , ( 2 , 2 ) , ( 3 , 3 ) , ( 4 , 4 ) } , R 6 = { ( 1 , 3 ) , ( 1 , 4 ) , ( 2 , 3 ) , ( 2 , 4 ) , ( 3 , 1 ) , ( 3 , 4 ) } , Which of the following statements are correct? Check ALL correct answers below. A. R 2 is not transitive B. R 4 is antisymmetric C. R 5 is transitive D. R 6 is symmetric E. R 3 is transitive F. R 3 is reflexive G. R 3 is symmetric H. R 2 is reflexive I. R 4 is transitive J. R 5 is not reflexive K. R 4 is symmetric L. R 1 is not symmetric M. R 1 is reflexive
Let R be a relation on A = {0, 3, 4, 7} and R = {(0, 3), (3, 0), (7, 3), (4, 4), (7, 7), (3, 7), (3, 3)}. Are the following statements true or false? ? ? ? ? ? ? 1. R is symmetric ↑ 2. R is anti-symmetric 3. R is transitive ◆ 4. R is reflexive 5. R is a partial order ♦ 6. R is an equivalence relation
Please select all that apply.
Two-part question: Let R be a relation from X to Y and S be a relation from Y to Z. Prove or disprove if R and S are surjective, then so is S of R, and prove or disprove if the composition of S of R is surjective, then so is S.
let A= {a,b,c,d} and R= {(a,a),(a,c),(b,d),(c,a),(c,c),(d,b)} be a relation on A. What is the inverse of R?
Let P={1.2,3,4,12,36} and the relation set R={(1,1) ,(2,2),(3,3),(4,4),(12,12),(36,36),(1,2),(1,3),(1,4),(1,12),(1,36),(2,4)(2,12),(2,36),(3,12),(3,26),(4,12),(4,36)}. Show that (P,R) is a poser. Represent the relation using the diagraph and then draw the Hasse diagram.

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Module 4 Discussion X Module 4 Discussion X What is Antireflexive (or irreflexive)? Consider the relation S on set (a, b, c} given by S = {(a, a),(a, b), (b, a), (b, b), (c, c), (b, c), (c, b)} Prove S is reflexive. Prove S is symmetric. Show S is not an equivalence relation. Module 4 Discuss