Consider the following time series data. 2 3 4 5 6 Week 1 Value 19 12 14 10 16 13 (a) Construct a time series plot. What type of pattern exists in the data? O The data appear to follow a seasonal pattern. O The data appear to follow a horizontal pattern. The data appear to follow a trend pattern. O The data appear to follow a cyclical pattern. (b) Develop the three-week moving average for this time series. (Round your answers to two decimal places.) Time Series Week Forecast Value 19 2 12 3 14 4 10 16 13 Compute MSE. (Round your answer to two decimal places.) MSE = What is the forecast for week 7?

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Consider the following time series data.
2|345
Week
1
Value
19
12
14
10
16
13
(a) Construct a time series plot. What type of pattern exists in the data?
O The data appear to follow a seasonal pattern.
O The data appear to follow a horizontal pattern.
The data appear to follow a trend pattern.
O The data appear to follow a cyclical pattern.
(b) Develop the three-week moving average for this time series. (Round your answers to two decimal places.)
Time Series
Value
Week
Forecast
1
19
12
3
14
10
16
13
Compute MSE. (Round your answer to two decimal places.)
MSE =
What is the forecast for week 7?
Transcribed Image Text:Consider the following time series data. 2|345 Week 1 Value 19 12 14 10 16 13 (a) Construct a time series plot. What type of pattern exists in the data? O The data appear to follow a seasonal pattern. O The data appear to follow a horizontal pattern. The data appear to follow a trend pattern. O The data appear to follow a cyclical pattern. (b) Develop the three-week moving average for this time series. (Round your answers to two decimal places.) Time Series Value Week Forecast 1 19 12 3 14 10 16 13 Compute MSE. (Round your answer to two decimal places.) MSE = What is the forecast for week 7?
(c) Use a = 0.2 to compute the exponential smoothing values for the time series.
Time Series
Value
Week
Forecast
1
19
2
12
3
14
4
10
5
16
6
13
Compute MSE. (Round your answer to two decimal places.)
MSE =
What Is the forecast for week 7? (Round your answer to two decimal places.)
(d) Compare the three-week moving average forecast with the exponentlal smoothing forecast using a = 0.2. Which appears to provide the better forecast based on MSE? Explaln.
O The three-week moving average provides
better forecast since It has a smaller MSE than the smoothing approach using a = 0.2.
O The exponential smoothing using a = 0.2 provides a better forecast since it has a smaller MSE than the three-week moving average approach.
O The exponential smoothing using a = 0.2 provides a better forecast since it has a larger MSE than the three-week moving average approach.
O The three-week moving average provides a better forecast since it has a larger MSE than the smoothing approach using a = 0.2.
(e) Use trial and error to find a value of the exponential smoothing coefficient a that results in a smaller MSE than what you calculated for a = 0.2.
Transcribed Image Text:(c) Use a = 0.2 to compute the exponential smoothing values for the time series. Time Series Value Week Forecast 1 19 2 12 3 14 4 10 5 16 6 13 Compute MSE. (Round your answer to two decimal places.) MSE = What Is the forecast for week 7? (Round your answer to two decimal places.) (d) Compare the three-week moving average forecast with the exponentlal smoothing forecast using a = 0.2. Which appears to provide the better forecast based on MSE? Explaln. O The three-week moving average provides better forecast since It has a smaller MSE than the smoothing approach using a = 0.2. O The exponential smoothing using a = 0.2 provides a better forecast since it has a smaller MSE than the three-week moving average approach. O The exponential smoothing using a = 0.2 provides a better forecast since it has a larger MSE than the three-week moving average approach. O The three-week moving average provides a better forecast since it has a larger MSE than the smoothing approach using a = 0.2. (e) Use trial and error to find a value of the exponential smoothing coefficient a that results in a smaller MSE than what you calculated for a = 0.2.
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