Consider the following system at equilibrium where AH° = 16.1 kJ/mol, and Kc = 6.50x10-3, at 298 K. 2 NOBr (g) = 2 NO (g) + Br₂ (g) When 0.19 moles of NOBr (g) are added to the equilibrium system at constant temperature: The value of Kel The value of Qc Кс. The reaction must Orun in the forward direction to restablish equilibrium. Orun in the reverse direction to restablish equilibrium. O remain the same. It is already at equilibrium. The concentration of NO will
Consider the following system at equilibrium where AH° = 16.1 kJ/mol, and Kc = 6.50x10-3, at 298 K. 2 NOBr (g) = 2 NO (g) + Br₂ (g) When 0.19 moles of NOBr (g) are added to the equilibrium system at constant temperature: The value of Kel The value of Qc Кс. The reaction must Orun in the forward direction to restablish equilibrium. Orun in the reverse direction to restablish equilibrium. O remain the same. It is already at equilibrium. The concentration of NO will
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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R
Q
Consider the following system at equilibrium where AH° = 16.1 kJ/mol, and Kc =
6.50x10-3, at 298 K.
2 NOBr (g) 2 NO (g) + Br₂ (g)
When 0.19 moles of NOBr (g) are added to the equilibrium system at constant
temperature:
The value of Kel
The value of Qcl
%
5
The reaction must
Orun in the forward direction to restablish equilibrium.
Orun
the reverse direction to restablish equilibrium.
O remain the same. It is already at equilibrium.
The concentration of NO will
✔
Use the References to access important values if needed for this question.
T
G
Submit Answer
B
e
F5
A
6
Y
H
FO
N
Retry Entire Group
&
7
K
Kc.
F7
U
*
8
M
DII
FB
1
References
9 more group attempts remaining
K
(
9
DD
O
O
F10
P
F11
Previous Next>
{
F12
delete"
Transcribed Image Text:7
$
R
Q
Consider the following system at equilibrium where AH° = 16.1 kJ/mol, and Kc =
6.50x10-3, at 298 K.
2 NOBr (g) 2 NO (g) + Br₂ (g)
When 0.19 moles of NOBr (g) are added to the equilibrium system at constant
temperature:
The value of Kel
The value of Qcl
%
5
The reaction must
Orun in the forward direction to restablish equilibrium.
Orun
the reverse direction to restablish equilibrium.
O remain the same. It is already at equilibrium.
The concentration of NO will
✔
Use the References to access important values if needed for this question.
T
G
Submit Answer
B
e
F5
A
6
Y
H
FO
N
Retry Entire Group
&
7
K
Kc.
F7
U
*
8
M
DII
FB
1
References
9 more group attempts remaining
K
(
9
DD
O
O
F10
P
F11
Previous Next>
{
F12
delete
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