Suggest four ways in which the concentration of PH3 could be increased in an equilibrium described by the following equation: P4 (g) + 6H₂ (8)= 4PH3 (8) ΔΗ= 110 5 kJ

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**Ways to Increase the Concentration of PH₃ in an Equilibrium Reaction**

In a chemical equilibrium reaction described by the equation:

\[ \mathbf{P_4 (g) + 6H_2 (g) \leftrightarrow 4PH_3 (g)} \]

with \( \Delta H = 110.5 \text{ kJ} \),

there are several strategies to increase the concentration of phosphine (PH₃). Here are four ways to achieve this:

1. **Increase the Pressure:**
   - In gaseous reactions, increasing the pressure tends to favor the side of the equilibrium with fewer gas molecules.
   - Here, 7 moles of gas (1 mole of P₄ and 6 moles of H₂) turn into 4 moles of PH₃ gas. Increasing the pressure will shift the equilibrium to the right, favoring the production of PH₃.

2. **Decrease the Temperature:**
   - The given reaction has a positive ΔH value, indicating that it is endothermic.
   - Lowering the temperature will shift the equilibrium position to the right to counteract the removal of heat, therefore increasing the formation of PH₃.

3. **Increase the Concentration of Reactants:**
   - According to Le Chatelier's Principle, increasing the concentration of the reactants (P₄ or H₂) will shift the equilibrium toward the products to counterbalance the change.
   - Therefore, by adding more P₄ or H₂, the system will produce more PH₃.

4. **Remove PH₃ as it Forms:**
   - Continuously removing PH₃ gas from the reaction vessel as it forms will shift the equilibrium to the right, promoting the formation of more PH₃.
   - This can be done using various separation techniques such as condensation or absorption.

By employing these strategies, the concentration of PH₃ in the equilibrium system can be increased.
Transcribed Image Text:**Ways to Increase the Concentration of PH₃ in an Equilibrium Reaction** In a chemical equilibrium reaction described by the equation: \[ \mathbf{P_4 (g) + 6H_2 (g) \leftrightarrow 4PH_3 (g)} \] with \( \Delta H = 110.5 \text{ kJ} \), there are several strategies to increase the concentration of phosphine (PH₃). Here are four ways to achieve this: 1. **Increase the Pressure:** - In gaseous reactions, increasing the pressure tends to favor the side of the equilibrium with fewer gas molecules. - Here, 7 moles of gas (1 mole of P₄ and 6 moles of H₂) turn into 4 moles of PH₃ gas. Increasing the pressure will shift the equilibrium to the right, favoring the production of PH₃. 2. **Decrease the Temperature:** - The given reaction has a positive ΔH value, indicating that it is endothermic. - Lowering the temperature will shift the equilibrium position to the right to counteract the removal of heat, therefore increasing the formation of PH₃. 3. **Increase the Concentration of Reactants:** - According to Le Chatelier's Principle, increasing the concentration of the reactants (P₄ or H₂) will shift the equilibrium toward the products to counterbalance the change. - Therefore, by adding more P₄ or H₂, the system will produce more PH₃. 4. **Remove PH₃ as it Forms:** - Continuously removing PH₃ gas from the reaction vessel as it forms will shift the equilibrium to the right, promoting the formation of more PH₃. - This can be done using various separation techniques such as condensation or absorption. By employing these strategies, the concentration of PH₃ in the equilibrium system can be increased.
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