The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K.Calculate Ke for this reaction at this temperature.CPC15 (g) → PC13(g) + Cl₂ (9)Kc=|| The equilibrium constant, Kp, for the following reaction is 0.215 at 673 K.Calculate Ke for this reaction at this temperature.CNH4I(s)→NH3(g)+HI(g)Kc=||

Answered: The equilibrium constant, K₂, for the…

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 15P

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The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K.
Calculate Ke for this reaction at this temperature.
C
PC15 (g) → PC13(g) + Cl₂ (9)
Kc
=
||

The equilibrium constant, Kp, for the following reaction is 0.215 at 673 K.
Calculate Ke for this reaction at this temperature.
C
NH4I(s)→NH3(g)+HI(g)
Kc
=
||

Expert Solution

Step 1: Relation between equilibrium constant Kp and Kc

Answer:

$straight K subscript straight C equals straight K subscript straight P left parenthesis RT right parenthesis to the power of negative increment straight n subscript straight g end exponent$

Here:

$straight R equals universal space gas space constant straight T equals Temperature space left parenthesis in space straight K right parenthesis increment straight n subscript straight g equals change space in space number space of space gaseous space moles$

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