Consider the following set of processes,assumed to have arrived as shown in the tablebelow with the length of the CPU burst given inmilliseconds:ArrivalTimeBurstProcessPriorityTimeP184P26.1P321P419.P5Suppose that the processes arrive in theorder: P1, P4, P3, P2, P5. The Time quantumis 2 milliseconds. Using Non-preemptive Priority scheduling algorithm, fillup the following table:Waiting TurnaroundTimeResponseTimeTimeP1P2P3P4P5Average

Answered: Consider the following set of…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Consider the FIVE (5)process with their CPU burst time and arrival time. Process Arrival Time CPU burst time P0 0 1 P1 2 3 P2 1 4 P3 1 3 P4 3 2 Based on the above data, answer the following Draw a time line for the following algorithm: Shortest Job First (SJF) Shortest Remaining Time (SRT)
4. Consider a system which has logical address is 7 bits, physical address is 6 bits calculate the number of pages and no.of frames. 5. Given Memory partition of 110,510K,210K and310kand600kin that order show how each of the best-fit, worst-fit and first-fit algorithms place process of221,471,112and 426 in that order in memory.
V. Round Robin and SJF comparison Process Arrival Time CPU Burst Time P1 9. P2 4 4 P3 1 P4 8. For each of the following algorithms, draw a Gantt chart and calculate the average wait time and turn around time. 1. Reund robin with quantum=1 time unit 2. Round-robin with quantum=3 time-units 3. SJF W/ preemptien (Shertest Remaining Time First), assume quantum=3 4. SJF wlo preemption 5. FGFS
Draw the Gantt Chart of the sequence of execution of the processes using Round RobinScheduling Algorithm considering the arrival time for all the process as ‘0’ and the quantum time as ‘3’. Find the average waiting time of the processes.
Suppose that we have the table below that includes four processes with their Arrival times and Burst times, and a Round Robin of time quantum 1 millisecond to be used for CPU scheduling. Answer the following questions: Process Arrival CPU-burst ID time time P1 0 1 P2 3 3 P3 2 4 P4 4 3 Completion Time Response Turn Around Time Time Waiting Time a. Draw the Gantt chart. b. Complete the above table. c. Calculate the average waiting time.
Consider the following set of four processes. Their arrival time and time to require completing the execution are given in the following table. Consider all times in milliseconds. Implement the SJF algorithm on given chart. Process Arrival Time (T0) Time required for completion (CPU Burst Time) P0 0 10 P1 1 6 P2 3 2 P3 5 4
Consider the following processes with the given CPU arrival time and burst time. Please use the shortest remaining time first algorithm to compute for the CPU utilization
Consider the following set of 5 processes, with the length of the CPU-burst time given in milliseconds arriving at time 0: P1, P2, P3, P4, and P5 with corresponding burst time: 20, 47, 13, 17 and 22. The processes are assumed to have arrived in the order P1, P2, P3, P4, P5, all at time 0. a. Calculate average waiting time for First Come First Serve and None Preemptive Shortest Job First CPU scheduling algorithms. b. Which of the schedules in part a results in the minimal average waiting time (over all processes)?
Consider the following table of set of processes, assumed to have arrived at time 0 in the order P1, P2, P3, P4, P5, with the length of the CPU burst given in milliseconds. Process P1 P2 P3 P4 P5 CPU burst time 8 1 2 1 5 2. Non-Preemptive Priority. 3. RR (Time Quantum = 6). Priority 5 1 3 4 2 a. Design the flow of processes in a Gantt chart using each of the following algorithms: 1. FCFS.
Draw the corresponding Gantt diagrams for this scheduling algorithms;- Round Robin q=1 (1ms Quantum).
consider the Round-Robin (RR) with quantum = 10 of the table below, Average waiting time of processes is: Process Burst Time Arrival Time P1 15 P2 3 P3 2 9.3 milliseconds 5 milliseconds 14.5 millisecond 20 milliseconds
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