Consider the following scenario/łassumptions: . A hash table can store at most 11 elements. Indices are numbered from 0 to 10. It is currently empty (no elements yet). • The hashing function is defined as H(k) = k % 11 • The collision resolution technique is Linear Probing. Insert the following keys in the hash table in the sequence that they appear below: • 172458 282459 • 392458 •502461 612458 • 722463 832458 • 942465 • 1052458 • 1162467 Write on a piece of paper the contents of the resulting has table after inserting these keys. The table should contain 10 elements, with only one address that is left open, i.e., it is not occupied by any key. Answer the questions below by filling up the blanks. 1. What is the address (array index) of the memory space that is still open? 2. What is H(722463)? 3. In which address (array index) was key 832458 stored? 4. Which key value was stored in address (array index) 8? 5. The value of H(k) is called k's home address. How many keys were not stored in their respective home addresses?

Consider the following scenario/łassumptions: . A hash table can store at most 11 elements. Indices are numbered from 0 to 10. It is currently empty (no elements yet). • The hashing function is defined as H(k) = k % 11 • The collision resolution technique is Linear Probing. Insert the following keys in the hash table in the sequence that they appear below: • 172458 282459 • 392458 •502461 612458 • 722463 832458 • 942465 • 1052458 • 1162467 Write on a piece of paper the contents of the resulting has table after inserting these keys. The table should contain 10 elements, with only one address that is left open, i.e., it is not occupied by any key. Answer the questions below by filling up the blanks. 1. What is the address (array index) of the memory space that is still open? 2. What is H(722463)? 3. In which address (array index) was key 832458 stored? 4. Which key value was stored in address (array index) 8? 5. The value of H(k) is called k's home address. How many keys were not stored in their respective home addresses?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Hash Table

A hash table also called a hash map, is a data structure that maps key-value pairs. The hash table can be used in complex systems to provide fast access and compact storage. A hash table is a structure that stores data in an abstract data type kind of associative array. It keeps data in an array format, with a distinct index value for every data value. If the index of the required data is known, then the data can be accessed very easily.

Question

Consider the following scenario/assumptions:
. A hash table can store at most 11 elements. Indices are numbered from 0 to 10. It is currently empty (no elements yet).
• The hashing function is defined as H(k) = k % 11
. The collision resolution technique is Linear Probing.
Insert the following keys in the hash table in the sequence that they appear below:
• 172458
• 282459
• 392458
• 502461
• 612458
• 722463
832458
• 942465
1052458
• 1162467
Write on a piece of paper the contents of the resulting has table after inserting these keys. The table should contain 10 elements, with only one address that is left
open, i.e., it is not occupied by any key. Answer the questions below by filling up the blanks,
1. What is the address (array index) of the memory space that is still open?
2. What is H(722463)?
3. In which address (array index) was key 832458 stored?
4. Which key value was stored in address (array index) 8?
5. The value of H(k) is called k's home address. How many keys were not stored in their respective home addresses?

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