Consider the following scenario/łassumptions: . A hash table can store at most 11 elements. Indices are numbered from 0 to 10. It is currently empty (no elements yet). • The hashing function is defined as H(k) = k % 11 • The collision resolution technique is Linear Probing. Insert the following keys in the hash table in the sequence that they appear below: • 172458 282459 • 392458 •502461 612458 • 722463 832458 • 942465 • 1052458 • 1162467 Write on a piece of paper the contents of the resulting has table after inserting these keys. The table should contain 10 elements, with only one address that is left open, i.e., it is not occupied by any key. Answer the questions below by filling up the blanks. 1. What is the address (array index) of the memory space that is still open? 2. What is H(722463)? 3. In which address (array index) was key 832458 stored? 4. Which key value was stored in address (array index) 8? 5. The value of H(k) is called k's home address. How many keys were not stored in their respective home addresses?

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Consider the following scenario/assumptions:
. A hash table can store at most 11 elements. Indices are numbered from 0 to 10. It is currently empty (no elements yet).
• The hashing function is defined as H(k) = k % 11
. The collision resolution technique is Linear Probing.
Insert the following keys in the hash table in the sequence that they appear below:
• 172458
• 282459
• 392458
• 502461
• 612458
• 722463
832458
• 942465
1052458
• 1162467
Write on a piece of paper the contents of the resulting has table after inserting these keys. The table should contain 10 elements, with only one address that is left
open, i.e., it is not occupied by any key. Answer the questions below by filling up the blanks,
1. What is the address (array index) of the memory space that is still open?
2. What is H(722463)?
3. In which address (array index) was key 832458 stored?
4. Which key value was stored in address (array index) 8?
5. The value of H(k) is called k's home address. How many keys were not stored in their respective home addresses?
Transcribed Image Text:Consider the following scenario/assumptions: . A hash table can store at most 11 elements. Indices are numbered from 0 to 10. It is currently empty (no elements yet). • The hashing function is defined as H(k) = k % 11 . The collision resolution technique is Linear Probing. Insert the following keys in the hash table in the sequence that they appear below: • 172458 • 282459 • 392458 • 502461 • 612458 • 722463 832458 • 942465 1052458 • 1162467 Write on a piece of paper the contents of the resulting has table after inserting these keys. The table should contain 10 elements, with only one address that is left open, i.e., it is not occupied by any key. Answer the questions below by filling up the blanks, 1. What is the address (array index) of the memory space that is still open? 2. What is H(722463)? 3. In which address (array index) was key 832458 stored? 4. Which key value was stored in address (array index) 8? 5. The value of H(k) is called k's home address. How many keys were not stored in their respective home addresses?
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