Suppose you have a hash table of size N = 64, and you are using quadratic probing with c1 = 1 and c2 = 1. The keys in your hash are 4-digit integers (0000 through 9999) and your hash function is h(k) = (the sum of the digits in k). What are the first 4 values in the search sequence (starting with the home position) for a record with key k=1948? Blank # 1 Blank # 2 Blank # 3 Blank # 4
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- Using the values provided below, show the hash key and what the hash table will look like when using the two different techniques indicated. The hash function used is based upon the first letter of the person's last name. The array size is 27 Index 0 is not used The letter 'A' will go to index 1, 'B' to index 2, etc Separate chaining Open addressing with linear probing i_table = ( h(k) + j ) mod S where i is the index of the underlying array,h is the hash function,j is the iteration of the probe, andS is the size of the table Values needing to be hashed (in order from top to bottom) Big Bird The Penguin Jackie Chan The Joker The Riddler Lewis Carroll Arthur Doyle Clark Kent Clive Lewis Lois Lane Yogi Bear Charles Dickens Geoffrey Chaucer Mr Ranger William Shakespeare John Tolkien Fred RogersYou are asked to insert the following values into the hashing table size 9: 9, 18, 19, 27, 8, 17. Use linear probing if there is a collision. Your answer will be in the form of the order of inserted elements. The order of inserted elements:: 9 18 19 - - 27 8 - 17 The order of inserted elements: 9 18 19 27 - - 17 - 8 O The order of inserted elements: 9 18 19 27 17 - - -8 O The order of inserted elements: 9 18 19 27 8 - -17 -Suppose you are told to implement a open hash table that has at most 12,000 buckets and you expect to use up at most a half of that. What is the average number of attempts you expect to experience for any particular query? Round to the nearest 2 decimal places if necessary.
- If N items are inserted into a hash tabble of size H, what is the expected average chain length?Consider a hash table of size 100 named marks Table that uses linear probing and a hash function of key % 5. What would be the hash table index (0-based) of key 46? marks Table.insert(47); marks Table.insert(41); marks Table.insert(42); marks Table.insert(44); marks Table.insert(46);You're tracking information on rocket launches. Each launch is assigned a number from 1000 to 100000. There will probably be around 5000 launches, and you're using a hashing algorithm that divides the highest possible number of launches by the expected number of launches. What is the hashing algorithm key in this situation? a. 200 b. 20 c. 500000 d. 5000000
- Does a hash table of size m consistently contain the same number of linked lists? I am unable to identify the purpose of a hash function, no matter how hard I attempt. To demonstrate your thesis, provide an example.All of these statements are related to hash function, hash table.Suppose you have a hash table of size N = 64, and you are using quadratic probing. The keys in your hash are 4-digit integers (0000 through 9999) and your hash function is h(k) = (the sum of the digits in k). Assuming keys are uniformly random over the range 0000 to 9999, is this a good hash function? (Answer true for yes, false for no). True False
- Consider a open bucket hash table and closed bucket hash table in which the keys are student identifiers (strings of 6 digits). Assume the following number of buckets and hash function: m = 100; hash(id) = first two digits of id #. Starting with an empty hash table, show the effect of successively adding the following student identifiers: 000014, 990021, 990019, 970036, 000015, 970012, 970023. Use following function as second hash function hash(id) = last digit of id # Show the effect of deleting 000014 from the hash table. (Java Programming DSA)Does a hash table of size m always have the same number of linked lists? No matter how long I try, I just can't put my finger on the function of a hash function. Give a case study to demonstrate your point.Using double Hashing, insert items with keys: 69, 86, 33, 47, 17, 55 into an empty hash table. tableSize: 7 hash1(x) = x mod tableSize. hash₂(x) = R-(x mod R), R is a prime number smaller than tableSize hash1(x) + hash2(x) mod tableSize