Question 17Consider the following reaction:Br2 (1) + 21 (aq) =2Br (aq) + I2(s)Br2 + 2e 2Br E° = +1.09 V%3D12+ 2e 21-E° = +0.54 VCalculate the following.E° cell = [Select]%3Dequilibrium constant at 298 K = [Select]%3D<>

Answered: Image /qna-images/answer/8a5a858f-748c-409a-b165-185915e163fc.jpg

Consider the following reaction: Br2 (1) + 21- (aq) =2Br (aq) + 12(s) Br2 + 2e 2Br E° = +1.09 V 12+ 2e 21 E° = +0.54 V Calculate the following. E° cell [ Select ] %3D equilibrium constant at 298 K =[Select] <> <>

Consider the following reaction: Br2 (1) + 21- (aq) =2Br (aq) + 12(s) Br2 + 2e 2Br E° = +1.09 V 12+ 2e 21 E° = +0.54 V Calculate the following. E° cell [ Select ] %3D equilibrium constant at 298 K =[Select] <> <>

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: Consider the following reaction: 2 Ce+ (aq) + 2CI (aq) = Cl2 (g) + 2Ce3+ (aq) Ce4+ + e + Ce+ E° =…

Q: Consider the following reaction: O2 (g) + 4H* (ag) + 4FE²* (aq) 2H20 (1) + 4Fe3+ (aq) %3D O2+ 4H*…

A: E0cell = E0cathode-E0anode The half cell with higher the E0 - value when compared to other half cell…

Q: Calculate the potential measured for the following cell at 298 K. Cr(s) | Cr3+ (aq) (0.0055 M) ||…

Q: Consider the following cell. Cr | Cr³+ (1.00 M) || Ni²+(1.00 M) | Ni = 0.68 V (a) How many…

A: (b) Write the balanced chemical equation for the overall cell reaction and use the ICE table.

Q: Consider the following reaction at 298K. Cu²+ (aq) + Fe2+ (aq) →→ Cut (aq) + Fe3+ (aq) Which of the…

A: This problem is based on electrochemistry. We will check different parameters over here and try to…

Q: A galvanic cell is based on the following half reactions: Ag* + e > Ag (s) E° = 0.80 V Cu2+ + 2 e →…

A: The cell potential at a given temperature can be obtained by the following relation: E=E0-RTnFlnK…

Q: Given the following electrochemical cell, calculate the potential for the cell in which the…

Q: 2- Calculate E° cell for the following electrochemical cell: Ni(s) | Ni2*(aq) || Hg2*(aq) | Hg(I) E°…

A: Given electrochemical cell : We have to calculate the E0cell for the above cell.

Q: Calculate the equilibrium constant for the electrochemical cell represented by the following line…

A: The standard electrode potential (Eocell) of a cell can be calculated by: Ecell0=RTnFln K Here, R is…

Q: A voltaic cell was constructed based on the two reactions shown below: Reduction half reaction:…

Q: Reduction half-cells and their standard potentials are, respectively: N2 (g) + 4 H2O (l) + 4 e- →…

A: Answering the first three sub parts as per guidelines for further assistance please post the…

Q: An electrochemical cell is constructed with a Zn (s) electrode in contact with a 0.0520 M solution…

A: Given: Concentration of Zn2+ = 0.0520 M Concentration of Ag+ = 0.00420 M And temperature = 5.0 oC

Q: For the electrochemical cell Al(s) + 3 Mn²+ (aq) → 2 Al³+ (aq) + 3 Mn(s) (E° = 0.48 V, [A1³*] = 1.0…

Q: Equilibrium Constant from EMF Data Given are the standard reduction potentials for the two…

A: During a redox reaction, oxidation takes place at the anode and reduction takes place at the…

Q: If an electrochemical cell will be composed of the Hg electrode and Cr electrode, which one will…

A: The half cell reactions given are, 2 Hg2+(aq) + 2 e– → Hg22+ (aq) E°= 0.92 V Cr3+(aq)…

Q: e measured Eº value for the electrochemical cell: Cu(s) | Cu* (aq) || Pd2+ (aq) | Pd (s), is 0.390…

A: We have to determine new voltage of the cell.

Q: When the Cr2+ concentration increases, does the cell potential decrease, increase or stay the same?…

Q: Calculate the cell potential, the equilibrium constant, and the free-energy change for Ca(s)+ Mn²+,…

A: Electrochemistry question.

Q: For the galvanic (voltaic) cell Cd²*(aq) + Fe(s) – Cd(s) + Fe2*(aq) (E° = 0.0400 V), what is the…

Q: Determine E°, AGʻ, and K for the overall reaction from the balanced half-reactions and their…

Q: Give the cell notation 2Hg2+(aq) + 2e- Hg22+(aq); E°= 0.92 V Cr3+(aq) + 3e- Cr(s);…

A: Cell notation: It can be define as the shorthand method of describing a electrochemical cell…

Q: Br₂ (1) +21 (aq) → 2Br (aq) + 12(5) Express the energy change in kilojoules to two significant…

A: We can solve this problem by using the following equation ∆G° = -n×F×E° ∆G° = free energy change n…

Q: 22. Given: Cr** (ag) +3e Pb2* (aq) + 2e What is the standard cell potential for the following…

A: The standard cell potential can be calculated as

Q: A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard…

A: Standard reduction potential gives a measure of species which will act as a reducing agent and which…

Q: Consider the following reaction: 2 Al (s) + 3 12 (s)= 2A13+ (aq) + 61 (aq) 12+ 2e 21 E° = +0.54 V…

A: E0cell = E0cathode - E0anode The Half cell with higher standard reduction potential(E0) value when…

Q: Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free…

A: The reaction given is In the above reaction we can see that Mn in MnO2 is initially in 4+…

Q: a Calculate E° for the following cell: Hg | Hg22+ || Pb4", Pb2+ | Pt You may need to use the…

A: The answer to the following question is-

Q: 5. Followed from the previous question, it was determined that K for the reaction at 25°C between…

Q: Calculate the Kf of Ag(NH₃)₂ from Ag⁺(aq) +e⁻⇌Ag(s) E°=0.80 V ;Ag(NH₃)₂⁺(aq)+ e⁻⇌Ag(s)…

A: The given reactions along with their reduction potential values are, Ag+aq+e-↔Ags E°=0.80…

Q: Consider the following redox half-reaction at 25 °C: MnO4 (aq) + 8 H* (aq) + 5 e¯ → Mn²* (aq) + 4…

Q: Calculate the potential measured for the following cell at 298 K. Cr(s) | Cr³+ (aq) (0.0010 M) ||…

Q: The charge in the cell is raised until a reaction is achieved Given the following half equations:…

A: “Since you have asked multiple question, we will solve the first three questions for you. If you…

Q: The voltaic cell Ca(o)Ca²+ (aq) || Ni?+(1.0 M)|Ni(s) has a cell potential of 0.300 V at 25°C. What…

A: Given : Ecell = 0.300 V Temperature = 25 oC Concentration of Ni2+, [Ni2+ ] = 1.0 M And Eocell =…

Q: Be sure to answer all parts. 0 Balance the following skeleton reaction, calculate E cell Cu+(aq) +…

Q: What is the value of the equilibrium constant, K, at 298 K for the following reaction? Zn2+ (aq) + 2…

A: The reaction : T = 298 K

Q: 19.85 Calculate the cell potential of the following cell at 25°C. Cr(s) Cr **(1.0 x 10 ³ M) | |…

Q: 4. Calculate at which Zn² concentration (x) the following electrochemical cell has an EMF of 0.9 V.…

Q: What is the reduction potential for the half-reaction Al³+(aq) + 3e¯- Al(s) at 25°C if [A1³+] = 0.18…

A: The reaction is given as follows- Al3+ (aq) +3e- ------------> Al(s) T= 25°C [Al3+]=0.18E°=…

Q: What is the emf of this cell when [Fe2+] = 1.8 M, [Fe+] = 1.2x10-2 M , Po, = 0.55 atm , and the pH…

A: The voltaic cell reaction given is 4 Fe2+ (aq) + O2 (g) + 4 H+ (aq) → 4 Fe3+ (aq) + 2 H2O (l) The…

Q: 10. Use the standard reduction potentials, please calculate the AE and determine the spontaneity (AG…

Q: The following standard reduction potentials have been determined for the chemistry of indium:…

A: The objective of the question is to calculate the cell potential, E°, and the equilibrium constant,…

Q: Consider the following reaction: 2 Al (s) + 3 12 (s) = 2AI3+ (aq) + 61 (aq) 12 + 2e 21 E = +0.54 V…

A: Given,

Q: Calculate the pH of the cathode compartment for the following reaction given & cell = 3.01 V when…

A: Answer :----

Q: What is the value of the equilibrium constant, K, at 298 K for the following reaction? Zn2+ (aq) +…

Q: Calculate the value of AG at 25 °C for the cell described by the cell notation given below: Ti²+…

A: Standard reduction potential of both half cells is given. This will be used to calculate E°cell…

Q: Consider the following reaction: Br2 (1) + 21 (aq) 2Br (aq) + 12(s) Brz+ 2e 2Br E= +1.09 V 12+2e 21…

A: Relation between Gibbs free energy change and equilibrium constant ∆G = -2.303RTlog K - (1) Relation…

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

Calculate the cell potential for the following reaction and indicate whether it is spontaneous or not: 2Au(s) + 3Ca2*(aq) – 2Au3t(aq) + 3Ca(s) Au3+. * (aq) + Зе — Au(s) EO = 1.50 V Ca2+(aq) + 2e – Ca(S) EO = -2.87 V. O -4.37 V and spontaneous O -1.37 V and nonspontaneous O -4.37 V, nonspontaneous 4.37 V and spontaneous
Use the appropriate standard reduction potentials below to determine the equilibrium constant at 386 Kfor the following reaction under acidic conditions. 4H* (ag) + MnO, (s) +2Fe²*(aq) Mn²+ (aq) + 2Fe³+(aq) +2H,0(1) Standard reduction potentials: Mn²+ (aq) +2H,o(1) E° = 1.23 V MnO, (s) +4H*(aq) +2e¯ Fe+ (aq) +e¯ → Fe2+(ag) E° = 0.770 V
+ Complete and balance the following half-reaction in basic solution. Be sure to include the proper phases for all species within the reaction. Reset 2 Question 3 of 37 03 02 0 3 02 03 04 05 H₂O* OH™ - SO3² (aq) → SO4² (aq) 4 ( ) 1 O 5 02 03+04+ 6 7 8 06 07 0 H* H 9 Do t (s) (1) (g) (aq) S H₂O • H₂O Delete Submit
Consider the following reaction: O2 (g) + 4H* (aq) + 4FE2* (aq) = 2H20 (1) + 4FE3* (aq) O2 + 4H' + 4e" → 2H2O E° = +1.23 V Fe3+ + e → Fe?+ E° = +0.77 V Calculate the following. E° cell = +2.00 V AG° (in kJ/mol) = [Select ] > >
Pt(s) IX*(ag), X2+, ELECTROCHEMISTRY: (aq) | Y(s) Given the line notation: (aq) || y3+ where: x2+ + e - x+ E° = 0.94 V y3+ + 3 e → Y E° = -2.71 V Pt4+ + 4 e E° = 1.20 V Pt Calculate the EMF.
1
7-A fuel cell uses the following reduction half-reactions. O2(g) + 2H20(1) + 4e- 40H- (ag) E° = 0.401 V CO3-(aq) + 7H2O(1) + 8e– → CH«(g) + 100H-(ag) E° = 0.110 V Ja) What is the maximum cell voltage that can be generated (b) What is the overall cell reaction that occurs?
What is the pH in the cathode for the following galvanic cell made from the following two half reactions? The initial concentration of gold ion is 1.1x10-3 M, the initial concentration of permanganate is 6.42 M, and the Ecell is 0.15 V. Assume the temperature is 298K. Au3+(aq) + 3e- → Au(s) E° = 1.52 VMnO4-(aq) + 4H+(aq) 3e- → MnO2(s) + 2H2O(l) E° = 1.70 V
Determine E°, AG°, and K for the overall reaction from the balanced half-reactions and their standard reduction potentials. 4 Fe3+ + 2 H,0 4 Fe²+ + O, + 4H+ Fe3+ + e-= Fe²+ E° = 0.771 V 0, + 2 H* + 2 e¯2 H,0 E° = 1.229 V E° = V K = Is the overall reaction spontaneous as written? AG° = spontaneous not spontaneous
Consider the following reaction: 2 Ce (aq) + 2CI" (aq) Cl2 (g) + 2Ce3+ (aq) Ce + e → Ce E° = +1.61 V Cl2 + 2e 2CI E = +1.36 V Calculate the following. E cell = [Select] equilibrium constant ta 298K- [Select ]
What is the equilibrium constant (K) at 25°C for the following cell reaction? Fe(s) + Cd2+(aq)------>Fe2+(aq)+ Cd(s). E0 cell = 0.010 V. Please show all steps clearly to solution. Thanks
Which statement is correct for the cell with a notation Pt /Cl2(g)/Cl¯(aq) // Zn+2(aq)/Zn ? Cl2 + 2e- --> 2Cl¯ E°=1.360 V Zn+2 + 2e- --> Zn E°= - 0.760 V choose: This is an electrolytic cell. The anode of this cell is negative and the cathode is positive. Work is being done by the cell. This is a voltaic or galvanic cell.