Consider the following method: public static void mystery2d(int[][] a) { for (int r = 0; r < a.length; r++) { for (int c = 0; c < a[0].length - 1; c++) { if (a[r][c + 1] > a[r][c]) { a[r][c] = a[r][c + 1]; } } } } If a two-dimensional array numbers is initialized to store the following integers, what are its contents after the call shown? int[][] numbers = {{3, 4, 5, 6}, {4, 5, 6, 7}, {5, 6, 7, 8}}; mystery2d(numbers);

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Q: C++

A: In step 2, I provided the answer with a brief explanation...

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A: Here is your solution -

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Q: Output in C++

A: C++ PROGRAM:#include &lt;iostream&gt;void mystery(int x[], int n) {int temp; for(int i=0; i&lt;n / 2…