Consider the following IVP: x" - 4x' + 4x = 4e2t; x(0) = -1, x'(0) = -4 Find the general solution. A x(1) = e² (21² – 21 – 1 ) x(1) = -e(?–21+ 1) В – 21²+ 1) x(t) = D x(t) = e'(21²– t-2)

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