Solve the equation x" + 4x = 8(t), x(0)=0, x'(0) = 0 a. x(t)=sin(2t) b. x(t)=[1-e-²¹-2te-²¹] + µ(t − 2)(t − 2)e−2(t−21) - c. x(t)=2μ(t - π)е-(-)sin(t-1) d. x(t)=[2-e²Tu(t− π) + е¹¹µ(t − 2π)]e-²¹sint x(t) = [1 + μ(t− n)]sin(2t) e.

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