omeworkConsider the following hypothesis test:Ho: 262H₂H<62A sample of 140 is used and the population standard deviation is 14. Compute the p-value and state your conclusion for each of the following sample results. Use a = 0.05. Round.decimal places and p-value to four decimal places. f your answer is zero, enter "0". Enter negative value as negative number.a. 60.5z valueP-valueconclusionb. = 58.5* value-Select your answer - Hop-valueconclusion - Select your answer ✓ Hoc. = 56z valuep-valueconclusion - Select your answer ✓ Hod. = 64z-valuep-valueconclusion - Select your answer✓ Hovalue to two

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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State the hypotheses and identify the claim. Compute the test statistic Find the P-value. Make the decision. Write the conclusion. Assume all populations are normally distributed. Test all claims at 0.05 . Do male and female college students have the same distribution of living arrangements? Suppose that 250 randomly selected male college students and 300 randomly selected female college students were asked about their living arrangements. The results are in the table. Test the claim that male and female college students have the same distribution of living arrangement. Dormitory Apartment With Parents Other Males 72 84 49 45 Females 91 86 88 35
A golf association requires that golf balls have a diameter that is 1.68 inches. To determine if golf balls conform to the standard, a random sample of golf balls was selected. Their diameters are shown in the accompanying data table. Do the golf balls conform to the standards? Use the a= 0.05 level of significance. Click the icon to view the data table. - X Data Table Golf Ball Diameter (inches) First determine the appropriate hypotheses. 1.677 1.681 Ho ▼ 1.678 1.686 ▼ H₁ ▼ 1.684 1.673 (Type integers or decimals. Do not round.) 1.682 1.675 Help me solve this View an example H Type here to search O 3 4 F T Get more Bi a & 6 B 7 U hp a 1.682 1.685 1.684 1.685 Print O 9 Done (?) O 95°F Mostly sunny ^ ver 1:43 PM 6/18/2022
A golf analyst claims that the standard deviation of the 18-hole scores for a golfer is less than 2.9 strokes. State H0 and Ha in words and in symbols. Then determine whether the hypothesis test for this claim is left-tailed, right-tailed, or two-tailed. Explain your reasoning. State the null hypothesis in words and in symbols. Choose the correct answer below. A. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at least 2.9 strokes." The null hypothesis is expressed symbolically as, "H0: σ≥2.9." B. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is not 2.9 strokes." The null hypothesis is expressed symbolically as, "H0: σ≠2.9." C. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is less than 2.9 strokes." The null hypothesis is expressed symbolically as, "H0: σ<2.9." D. The null hypothesis expressed in…
Men Women H2 A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. 11 97.67°F 0.91°F 59 97.35°F 0.73°F a. Use a 0.05 significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses? OB. Ho H =H2 O A. Ho 4, 2H2 H: 1
Copy each table to the Word document and highlight theappropriate p-value. Under each table type the hypotheses, decision and summary, using the resultsfrom Excel, again you should not be doing the calculations by hand! A random sample of 16 students selected from the student body of a large university was selected. We wantto determine if the average age of all the students at the university is significantly different from 24. Assumethe distribution of the population of ages is normal. t-Test: Paired Two Sample for Means Variable 1 Variable 2 Mean 22.8125 0 Variance 10.5625 0 Observations 16 16 Pearson Correlation #DIV/0! Hypothesized Mean Difference 24 df 15 t Stat -1.461538462 P(T<=t) one-tail 0.082249947 t Critical one-tail 1.753050356 P(T<=t) two-tail 0.164499893 t Critical two-tail 2.131449546 I am struggling with the explanation. How would I write this out? Thanks!
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
Suppose that you want to perform a hypothesis test for a population mean. Assume that the population standard deviation is unknown and that the sample size is relatively small. In each part, the distribution shape of the variable under consideration is given. Decide whether you would use the t-test, the Wilcoxon signed-rank test, or neither. a. Triangular b. Symmetric bimodal c. Left skewed
Three students were applying to the same graduate school. They came from schools with different grading systems. Thuy is Vichet is Kamala is Number Number Student GPA School Thuy Number 2.5 Vichet 86 Table 2.74 School Average 2.8 80 Kamala 8.5 8.3 How many standard deviations is each student away from hiir school average? If the student GPA is higher than his school average, enter this as a positive number. If the student GPA is lower than his school average, enter this as a negative number. Average GPA GPA School Standard Deviation 0.8 10 0.5 standard deviations from Thuy's school average. standard deviations from Vichet's school average. standard deviations from Kamala's school average.
Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Refer to the accompanying data set. Use a 0.05 significance level to test the claim that women and men have the same mean diastolic blood pressure. a. The test statistic is (Round to two decimal places as needed.) b. The P-value is (Round to three decimal places as needed.)
Please solve
A golf analyst claims that the standard deviation of the 18-hole scores for a golfer is at most 3.1 strokes. State Ho and H, in words and in symbols. Then determine whether the hypothesis test for this claim is left-tailed, right-tailed, or two-tailed. Explain your reasoning. ..... State the null hypothesis in words and in symbols. Choose the correct answer below. A. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is not 3.1 strokes." The null hypothesis is expressed symbolically as, "Ho: σ7 3.1." B. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at least 3.1 strokes." The null hypothesis is expressed symbolically as, "Ho: o2 3.1." C. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at most 3.1 strokes." The null hypothesis is expressed symbolically as, "Ho: os3.1." D. The null hypothesis expressed in words is, "the…
A golf analyst claims that the standard deviation of the 18-hole scores for a golfer is less than 1.5 strokes. State H, and H, in words and in symbols. Then determine whether the hypothesis test for this claim is left-tailed, right-tailed, or two-tailed. Explain your reasoning. State the null hypothesis in words and in symbols. Choose the correct answer below. O A. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at least 1.5 strokes." The null hypothesis is expressed symbolically as, "Ho: 02 1.5." O B. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at most 1.5 strokes." The null hypothesis is expressed symbolically as, "Ho:os1.5." O C. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is less than 1.5 strokes." The null hypothesis is expressed symbolically as, "Ho: o1.5." The hypothesis test is because the V contains

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