Consider the following electrolysis reactions. Ni²+2e → Ni(s) O₂ + 4H¹ + 4e →→ 2H₂O Calculate the potential that would need to be applied to deposit Ni(s) on a platinum electrode under the following conditions: [N₁²¹] = 0.125 M PO₂ = 1.00 bar Reell = 2.0 pH 3.00 Eº = -0.236 V Eº = 1.229 V = I = 35 mA overpotentials = 0.5000 V
Consider the following electrolysis reactions. Ni²+2e → Ni(s) O₂ + 4H¹ + 4e →→ 2H₂O Calculate the potential that would need to be applied to deposit Ni(s) on a platinum electrode under the following conditions: [N₁²¹] = 0.125 M PO₂ = 1.00 bar Reell = 2.0 pH 3.00 Eº = -0.236 V Eº = 1.229 V = I = 35 mA overpotentials = 0.5000 V
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![) Consider the following electrolysis reactions.
Ni2+2e → Ni(s)
O₂ + 4H + 4e → 2H₂O
[Ni²¹] = 0.125 M
PO₂
1.00 bar
Calculate the potential that would need to be applied to deposit Ni(s) on a platinum electrode
under the following conditions:
=
= -0.236 V
Reell = 2.0 2
pH = 3.00
Eº = 1.229 V
I = 35 mA
overpotentials = 0.5000 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8e46c4de-01e9-4eb6-9da8-8eaf0af836a4%2F0e3f82b1-549c-464e-8b41-ea40d5cef33e%2F7lh0ms_processed.jpeg&w=3840&q=75)
Transcribed Image Text:) Consider the following electrolysis reactions.
Ni2+2e → Ni(s)
O₂ + 4H + 4e → 2H₂O
[Ni²¹] = 0.125 M
PO₂
1.00 bar
Calculate the potential that would need to be applied to deposit Ni(s) on a platinum electrode
under the following conditions:
=
= -0.236 V
Reell = 2.0 2
pH = 3.00
Eº = 1.229 V
I = 35 mA
overpotentials = 0.5000 V
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