Consider the following data. 2 HF(g)(equilibrium arrow) H2(g) + F2(g) H = +537 kJ C(s) + 2 F2(g)(equilibrium arrow) CF4(g) H = -680 kJ C2H4(g)(equilibrium arrow) 2 C(s) + 2 H2(g) H = -52.3 kJ Use Hess's law to calculate H for the reaction below. 2 CF4(g) + 4 HF(g)(equilibrium arrow) C2H4(g) + 6 F2(g) H = _____ kJ
Consider the following data. 2 HF(g)(equilibrium arrow) H2(g) + F2(g) H = +537 kJ C(s) + 2 F2(g)(equilibrium arrow) CF4(g) H = -680 kJ C2H4(g)(equilibrium arrow) 2 C(s) + 2 H2(g) H = -52.3 kJ Use Hess's law to calculate H for the reaction below. 2 CF4(g) + 4 HF(g)(equilibrium arrow) C2H4(g) + 6 F2(g) H = _____ kJ
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Consider the following data.
2 HF(g)(equilibrium arrow) H2(g) + F2(g) H = +537 kJ
C(s) + 2 F2(g)(equilibrium arrow) CF4(g) H = -680 kJ
C2H4(g)(equilibrium arrow) 2 C(s) + 2 H2(g) H = -52.3 kJ
Use Hess's law to calculate H for the reaction below.
2 CF4(g) + 4 HF(g)(equilibrium arrow) C2H4(g) + 6 F2(g)
H = _____ kJ
Expert Solution
Step 1
The given reaction is,
The steps for the given reaction are,
2HF(g) H2(g) + F2(g) H1 = +537 kJ ..............(1)
C(s) + 2 F2(g)CF4(g) H2 = -680 kJ ...............(2)
C2H4(g) 2C(s) + 2 H2(g) H3 = -52.3 kJ ............(3)
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