Types of Chemical Bonds
The attractive force which has the ability of holding various constituent elements like atoms, ions, molecules, etc. together in different chemical species is termed as a chemical bond. Chemical compounds are dependent on the strength of chemical bonds between its constituents. Stronger the chemical bond, more will be the stability in the chemical compounds. Hence, it can be said that bonding defines the stability of chemical compounds.
Polarizability In Organic Chemistry
Polarizability refers to the ability of an atom/molecule to distort the electron cloud of neighboring species towards itself and the process of distortion of electron cloud is known as polarization.
Coordinate Covalent Bonds
A coordinate covalent bond is also known as a dative bond, which is a type of covalent bond. It is formed between two atoms, where the two electrons required to form the bond come from the same atom resulting in a semi-polar bond. The study of coordinate covalent bond or dative bond is important to know about the special type of bonding that leads to different properties. Since covalent compounds are non-polar whereas coordinate bonds results always in polar compounds due to charge separation.
I don't reallt understand. I know I'm supposed to switch the sign but I don't see that reaction on the table. Keep in mind sig figs too. TYSM :)
![# Calculating Enthalpy for a Chemical Reaction
## Problem Statement
Using the table provided, what is the enthalpy for the reaction shown below:
\[ \mathbf{N_2(g) + 4H_2(g) + I_2(g) \rightarrow 2NH_3(g) + 2HI(g)} \]
## Instructions
- Retrieve the necessary enthalpy values for the reactants and products from the provided table.
- Apply Hess's Law, which involves summing the enthalpy changes of the products and subtracting the enthalpy changes of the reactants to find the enthalpy change for the reaction.
## Sample Input Box
\[ \text{Place the calculated enthalpy value here: } \]
[__________]
For detailed instructions and additional resources, please refer to the provided table in the course materials.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2dc05801-0f2f-4b82-9bd0-eb38a3fb827a%2F4b91a2d3-0110-48aa-ab1f-52300a85f09b%2Frwp8vrj_processed.png&w=3840&q=75)

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