Consider the first-order reaction described by the equation H,C– CH, H-C- -с —н H H Cyclopropane Propene At a certain temperature, the rate constant for this reaction is 5.84 × 104s-!. Calculate the half-life of cyclopropane at this temperature. - מו4 Given an initial cyclopropane concentration of 0.00700 M, calculate the concentration of cyclopropane that remains after 1.70 hours. concentration:

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
100%
### First-Order Reaction: Cyclopropane to Propene

**Consider the first-order reaction described by the equation:**

![Cyclopropane to Propene Reaction Diagram](image-url)

**Cyclopropane** (C₄H₆) transforms into **Propene** (C₃H₆) as shown in the chemical equation below:

\[ \text{Cyclopropane} \rightarrow \text{Propene} \]

At a certain temperature, the rate constant for this reaction is given as \( 5.84 \times 10^{-4} \, \text{s}^{-1} \).

#### Calculate the half-life of cyclopropane at this temperature:

The half-life ( \( t_{1/2} \) ) of a first-order reaction is calculated using the formula:

\[ t_{1/2} = \frac{0.693}{k} \]

where:
- \( t_{1/2} \) is the half-life,
- \( k \) is the rate constant.

\[ t_{1/2} = \]

[**Input box for the half-life calculation in seconds**]

---

#### Given an initial cyclopropane concentration of 0.00700 M, calculate the concentration of cyclopropane that remains after 1.70 hours.

For a first-order reaction, the relationship between the concentration of the reactant at a given time \( t \) and the rate constant \( k \) is given by:

\[ [A]_t = [A]_0 e^{-kt} \]

where:
- \([A]_t\) is the concentration at time \( t \),
- \([A]_0\) is the initial concentration,
- \( k \) is the rate constant,
- \( t \) is the time.

Convert 1.70 hours to seconds (since \( k \) is in \( \text{s}^{-1} \)):

\[ t = 1.70 \, \text{hours} \times 3600 \, \text{s/hour} \]

Then calculate:

[**Input box for the concentration calculation in Molarity (M)**]

#### Explanation of Diagrams:
- **Cyclopropane (structure on the left)**: Three carbon atoms form a triangle with each carbon bonded to two hydrogen atoms (\( C_3H_6 \)).
  
- **Reaction Arrow**
Transcribed Image Text:### First-Order Reaction: Cyclopropane to Propene **Consider the first-order reaction described by the equation:** ![Cyclopropane to Propene Reaction Diagram](image-url) **Cyclopropane** (C₄H₆) transforms into **Propene** (C₃H₆) as shown in the chemical equation below: \[ \text{Cyclopropane} \rightarrow \text{Propene} \] At a certain temperature, the rate constant for this reaction is given as \( 5.84 \times 10^{-4} \, \text{s}^{-1} \). #### Calculate the half-life of cyclopropane at this temperature: The half-life ( \( t_{1/2} \) ) of a first-order reaction is calculated using the formula: \[ t_{1/2} = \frac{0.693}{k} \] where: - \( t_{1/2} \) is the half-life, - \( k \) is the rate constant. \[ t_{1/2} = \] [**Input box for the half-life calculation in seconds**] --- #### Given an initial cyclopropane concentration of 0.00700 M, calculate the concentration of cyclopropane that remains after 1.70 hours. For a first-order reaction, the relationship between the concentration of the reactant at a given time \( t \) and the rate constant \( k \) is given by: \[ [A]_t = [A]_0 e^{-kt} \] where: - \([A]_t\) is the concentration at time \( t \), - \([A]_0\) is the initial concentration, - \( k \) is the rate constant, - \( t \) is the time. Convert 1.70 hours to seconds (since \( k \) is in \( \text{s}^{-1} \)): \[ t = 1.70 \, \text{hours} \times 3600 \, \text{s/hour} \] Then calculate: [**Input box for the concentration calculation in Molarity (M)**] #### Explanation of Diagrams: - **Cyclopropane (structure on the left)**: Three carbon atoms form a triangle with each carbon bonded to two hydrogen atoms (\( C_3H_6 \)). - **Reaction Arrow**
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Knowledge Booster
Rate Laws
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY