What is the half-life (in seconds) of a zero-order reaction which has an initial reactant concentration of 0.824 Mwith a kvalue of 5.43 x 10-2 M/s?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Question:**

What is the half-life (in seconds) of a zero-order reaction which has an initial reactant concentration of 0.824 M with a k value of 5.43 × 10^-2 M/s?

**Answer Box:**
[_________] s

**Related Tools:**

- See Periodic Table

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**Explanation:**

In this question, you are asked to calculate the half-life of a zero-order reaction. In zero-order kinetics, the half-life is determined using the formula:

\[ t_{1/2} = \frac{[A]_0}{2k} \]

Where:  
- \([A]_0\) is the initial concentration, 0.824 M in this case.
- \(k\) is the rate constant, 5.43 × 10^-2 M/s.

You would plug these values into the formula to find the half-life in seconds.
Transcribed Image Text:Transcription for Educational Website: --- **Question:** What is the half-life (in seconds) of a zero-order reaction which has an initial reactant concentration of 0.824 M with a k value of 5.43 × 10^-2 M/s? **Answer Box:** [_________] s **Related Tools:** - See Periodic Table --- **Explanation:** In this question, you are asked to calculate the half-life of a zero-order reaction. In zero-order kinetics, the half-life is determined using the formula: \[ t_{1/2} = \frac{[A]_0}{2k} \] Where: - \([A]_0\) is the initial concentration, 0.824 M in this case. - \(k\) is the rate constant, 5.43 × 10^-2 M/s. You would plug these values into the formula to find the half-life in seconds.
Expert Solution
Step 1

Given that:

Initial reactant concentration [A] = 0.824 M

k = 5.43×10-2M/s

Half-life of zero order reaction t12 = ?

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