Consider the equilibrium system described by the chemical reaction below. At equilibrium, a sample of gas from the system is collected into a 2.50 L flask. The flask is found to contain 1.25 g of NO, 0.787 g of Br₂, and 11.6 g of NOBr at 297 K. What are the values of Kc and Kp for this reaction? Complete Parts 1-2 before submitting your answer. [0.0167] 1.65 x 10 7.68 x 10¹ Based on the given data, set up the expression for Kc. Each reaction participant must be represented by one tile. Do not combine terms. Once the expression is constructed, solve for Kc. [0.00197] [0.0167]² 54.1 Кс 1 = 2 NO(g) + Br₂(g) = 2 NOBr(g) [0.0422] [0.00197]² [0.0417] [0.0422]² 2 [0.00492] [0.0417]² [0.106] [0.00492]² 3.24 x 10³ NEXT [0.106]² RESET 1.29 × 10³ 3.09 x 10* >

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Consider the equilibrium system described by the chemical reaction below. At
equilibrium, a sample of gas from the system is collected into a 2.50 L flask. The
flask is found to contain 1.25 g of NO, 0.787 g of Br,, and 11.6 g of NOBr at 297
K. What are the values of Kc and Kp for this reaction? Complete Parts 1-2 before
submitting your answer.
[0.0167]
1.65 x 10⁰
7.68 × 104
Based on the given data, set up the expression for Kc. Each reaction participant must be
represented by one tile. Do not combine terms.
Once the expression is constructed, solve for Kc.
[0.00197]
[0.0167]²
54.1
Кс
1
=
2 NO(g) + Br₂(g) → 2 NOBr(g)
[0.0422]
[0.00197]²
[0.0417]
[0.0422]²
[0.00492]
[0.0417]²
2
||
[0.106]
[0.00492]²
3.24 × 10³
NEXT
[0.106]²
RESET
1.29 × 10³
>
3.09 × 10-4
Transcribed Image Text:Consider the equilibrium system described by the chemical reaction below. At equilibrium, a sample of gas from the system is collected into a 2.50 L flask. The flask is found to contain 1.25 g of NO, 0.787 g of Br,, and 11.6 g of NOBr at 297 K. What are the values of Kc and Kp for this reaction? Complete Parts 1-2 before submitting your answer. [0.0167] 1.65 x 10⁰ 7.68 × 104 Based on the given data, set up the expression for Kc. Each reaction participant must be represented by one tile. Do not combine terms. Once the expression is constructed, solve for Kc. [0.00197] [0.0167]² 54.1 Кс 1 = 2 NO(g) + Br₂(g) → 2 NOBr(g) [0.0422] [0.00197]² [0.0417] [0.0422]² [0.00492] [0.0417]² 2 || [0.106] [0.00492]² 3.24 × 10³ NEXT [0.106]² RESET 1.29 × 10³ > 3.09 × 10-4
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