2. Ozone can be created from oxygen gas (with an input of energy) via the following reaction: 302(8) = 203 (8) If the equilibrium constant, K, is 1.02 x 10-24 for this reaction at a particular temperature and [0₂] = 3.10 x 102 M at equilibrium, what is [03] (in M to two decimal places) at equilibrium? A: 5.51 x 10 -15
2. Ozone can be created from oxygen gas (with an input of energy) via the following reaction: 302(8) = 203 (8) If the equilibrium constant, K, is 1.02 x 10-24 for this reaction at a particular temperature and [0₂] = 3.10 x 102 M at equilibrium, what is [03] (in M to two decimal places) at equilibrium? A: 5.51 x 10 -15
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![2. Ozone can be created from oxygen gas (with an input of energy) via the following reaction:
30₂(8) = 203 (8)
-2
If the equilibrium constant, K, is 1.02 x 10-24 for this reaction at a particular temperature and
[0₂] = 3.10 x 10 M at equilibrium, what is [03] (in M to two decimal places) at equilibrium?
A: 5.51 x 10
-15
(2) (028 DES
(2)₂0+ (₂),025 = (8)¿025](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8e77b376-6a5c-4963-870c-f49a6e984799%2Fc073dc55-9986-49ea-a55b-9e9d25e40150%2F8jmkgmj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Ozone can be created from oxygen gas (with an input of energy) via the following reaction:
30₂(8) = 203 (8)
-2
If the equilibrium constant, K, is 1.02 x 10-24 for this reaction at a particular temperature and
[0₂] = 3.10 x 10 M at equilibrium, what is [03] (in M to two decimal places) at equilibrium?
A: 5.51 x 10
-15
(2) (028 DES
(2)₂0+ (₂),025 = (8)¿025
Expert Solution

Step 1
Since,
Equilibrium constant or Kc is the ratio of the equilibrium concentrations of product over equilibrium concentrations of reactants all raised to the power of their stoichiometric coefficients.
Then,
Step by step
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