The equilibrium
4 NH3(g) + 4 O2(g) ⇆ 2 N2O (g) + 6 H2O(l) ΔHo = −142 kJ/mol
Is established in a sealed container with a piston. Which of the following actions will increase the amount of the products present at equilibrium?
I Increasing the volume of the container
II Reducing the volume of the container
III Removing some of the H2O(l) from the container
IV Adding some NH3(g) to the container
V Adding N2(g) to the container
VI Raising the temperature
VII Lowering the temperature
The answer of the above questions are following
1-reducing the volume of the container
2- removing some of the H20 from the container (According to Lechatiler principle equilibrium will shift in forward direction)
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