Consider the equilibrium between PCl5, PCl3 and Cl2. PCl5(g) PCl3(g) + Cl2(g) K = 9.17×10-2 at 540 K The reaction is allowed to reach equilibrium in a 12.8-L flask. At equilibrium, [PCl5] = 0.112 M, [PCl3] = 0.102 M and [Cl2] = 0.102 M. (a) The equilibrium mixture is transferred to a 6.40-L flask. In which direction will the reaction proceed to reach equilibrium? (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 6.40-L flask. [PCl5] = M [PCl3] = M [Cl2] = M
Consider the equilibrium between PCl5, PCl3 and Cl2. PCl5(g) PCl3(g) + Cl2(g) K = 9.17×10-2 at 540 K The reaction is allowed to reach equilibrium in a 12.8-L flask. At equilibrium, [PCl5] = 0.112 M, [PCl3] = 0.102 M and [Cl2] = 0.102 M. (a) The equilibrium mixture is transferred to a 6.40-L flask. In which direction will the reaction proceed to reach equilibrium? (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 6.40-L flask. [PCl5] = M [PCl3] = M [Cl2] = M
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.98PAE
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Consider the equilibrium between PCl5, PCl3 and Cl2.
PCl5(g) PCl3(g) + Cl2(g) K = 9.17×10-2 at 540 K
The reaction is allowed to reach equilibrium in a 12.8-L flask. At equilibrium, [PCl5] = 0.112 M, [PCl3] = 0.102 M and [Cl2] = 0.102 M.
(a) The equilibrium mixture is transferred to a 6.40-L flask. In which direction will the reaction proceed to reach equilibrium?
(b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 6.40-L flask.
[PCl5] | = | M |
[PCl3] | = | M |
[Cl2] | = | M |
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