Consider the E2 elimination of 3‑bromopentane with hydroxide. The starting material consists of a chiral carbon with an in plane bond to bromine pointing to the upper left, an in plane bond to ethyl pointing to the right, a wedged bond to ethyl pointing to the lower left and a dashed bond to hydrogen pointing to the lower left. This reacts with hydroxide to form the product, water and bromide ion. Complete the curved arrow electron-pushing. Use three curved arrows to show the conversion to the product. Draw the organic product

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Consider the E2 elimination of 3‑bromopentane with hydroxide. The starting material consists of a chiral carbon with an in plane bond to bromine pointing to the upper left, an in plane bond to ethyl pointing to the right, a wedged bond to ethyl pointing to the lower left and a dashed bond to hydrogen pointing to the lower left. This reacts with hydroxide to form the product, water and bromide ion. Complete the curved arrow electron-pushing. Use three curved arrows to show the conversion to the product. Draw the organic product. 

Use three curved arrows to show the conversion to
the product.
Select Draw Templates More
H
: Br
с
H
H Br
H
0
H
Erase
Q2 Q
Draw the organic product.
Select Draw Templates More
|||||||||||| C H
O
Erase
Q2 Q
Transcribed Image Text:Use three curved arrows to show the conversion to the product. Select Draw Templates More H : Br с H H Br H 0 H Erase Q2 Q Draw the organic product. Select Draw Templates More |||||||||||| C H O Erase Q2 Q
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