Which of the following accurately shows the curved arrows for an E2 reaction? (A) (C) H (B) (D) H

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**Question:**
Which of the following accurately shows the curved arrows for an E2 reaction?

**Diagram Descriptions:**

**(A)**
- The diagram shows a tertiary amine on the left side with a lone pair of electrons.
- A curved arrow originates from the lone pair of the nitrogen and points towards a hydrogen atom on an adjacent cyclohexane ring.
- A second curved arrow points from the H atom’s bond to the bond between the carbon and iodine on the cyclohexane ring.
- The iodine is depicted leaving the molecule.

**(B)**
- Similar setup with a tertiary amine and cyclohexane.
- A single curved arrow originates from the lone pair on nitrogen directly to the iodine, bypassing the hydrogen.

**(C)**
- A tertiary amine is present with a lone pair of electrons.
- A curved arrow goes from the nitrogen's lone pair to the hydrogen atom on the cyclohexane ring.
- Another arrow goes from the H-C bond to the C-I bond, resulting in the iodine leaving.

**(D)**
- Again, there is a tertiary amine.
- A curved arrow comes from the lone pair on nitrogen to the hydrogen on cyclohexane.
- Another arrow goes directly from the C-I bond with no intermediate step via the H-C bond.

**Explanation:**
- Options (A) and (C) depict a two-step arrow process, involving both the H-C bond and C-I bond, typical for the abstraction step in an E2 reaction.
- Option (B) incorrectly suggests the lone pair attacks iodine directly.
- Option (D) misrepresents the positions and roles of bonds involved in a proper E2 elimination reaction.
Transcribed Image Text:**Question:** Which of the following accurately shows the curved arrows for an E2 reaction? **Diagram Descriptions:** **(A)** - The diagram shows a tertiary amine on the left side with a lone pair of electrons. - A curved arrow originates from the lone pair of the nitrogen and points towards a hydrogen atom on an adjacent cyclohexane ring. - A second curved arrow points from the H atom’s bond to the bond between the carbon and iodine on the cyclohexane ring. - The iodine is depicted leaving the molecule. **(B)** - Similar setup with a tertiary amine and cyclohexane. - A single curved arrow originates from the lone pair on nitrogen directly to the iodine, bypassing the hydrogen. **(C)** - A tertiary amine is present with a lone pair of electrons. - A curved arrow goes from the nitrogen's lone pair to the hydrogen atom on the cyclohexane ring. - Another arrow goes from the H-C bond to the C-I bond, resulting in the iodine leaving. **(D)** - Again, there is a tertiary amine. - A curved arrow comes from the lone pair on nitrogen to the hydrogen on cyclohexane. - Another arrow goes directly from the C-I bond with no intermediate step via the H-C bond. **Explanation:** - Options (A) and (C) depict a two-step arrow process, involving both the H-C bond and C-I bond, typical for the abstraction step in an E2 reaction. - Option (B) incorrectly suggests the lone pair attacks iodine directly. - Option (D) misrepresents the positions and roles of bonds involved in a proper E2 elimination reaction.
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