Consider the data path below for a single cycle 32-bits MIPS processor Assume that we are executing the following instruction lw St1, 48($10) What is the value of the element pointed by arrow number 1 by in hexadecimal? Note that the PC and the content of registers $10 and $t1 are found in bottom left of the figure below Data Memory Select one a. Ox00001724 Ob. 0x00002DE4 Oc 0x000016F4 Od 0x00001720 Oe. 0x00002DEO Clear my choice Rea " Address Content 0x000016EC 0x0000ABOD 0x000016F0 0x00A01245 0x000016F4 0x00001A42 0x000171C 0x0008124F 0x0001720 0x00021345 0x0001724 0x000067AB ALU Ox0001734 0x0000AB35 0x0001738 0x0000FA72 0x0000ABOC ALS 0x000174C Register File and PC $to = 0x000016FO $t1 = 0x000016F4 PC = 0x0000148A0 (Before executing LW)
Consider the data path below for a single cycle 32-bits MIPS processor Assume that we are executing the following instruction lw St1, 48($10) What is the value of the element pointed by arrow number 1 by in hexadecimal? Note that the PC and the content of registers $10 and $t1 are found in bottom left of the figure below Data Memory Select one a. Ox00001724 Ob. 0x00002DE4 Oc 0x000016F4 Od 0x00001720 Oe. 0x00002DEO Clear my choice Rea " Address Content 0x000016EC 0x0000ABOD 0x000016F0 0x00A01245 0x000016F4 0x00001A42 0x000171C 0x0008124F 0x0001720 0x00021345 0x0001724 0x000067AB ALU Ox0001734 0x0000AB35 0x0001738 0x0000FA72 0x0000ABOC ALS 0x000174C Register File and PC $to = 0x000016FO $t1 = 0x000016F4 PC = 0x0000148A0 (Before executing LW)
Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
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![Consider the data path below for a single cycle 32-bits MIPS processor
Assume that we are executing the following instruction
lw St1, 48($10)
What is the value of the element pointed by arrow number 1 by in hexadecimal?
Note that the PC and the content of registers $10 and $t1 are found in bottom left of the figure below
Data Memory
Select one
a. Ox00001724
Ob. 0x00002DE4
Oc 0x000016F4
Od 0x00001720
Oe. 0x00002DEO
Clear my choice
Rea
"
Address
Content
0x000016EC
0x0000ABOD
0x000016F0
0x00A01245
0x000016F4
0x00001A42
0x000171C
0x0008124F
0x0001720
0x00021345
0x0001724
0x000067AB
ALU
Ox0001734
0x0000AB35
0x0001738
0x0000FA72
0x0000ABOC
ALS
0x000174C
Register File and PC
$to = 0x000016FO
$t1 = 0x000016F4
PC = 0x0000148A0
(Before executing LW)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb237f50d-45a7-43af-805a-10c481d02971%2F9b5812db-f689-4e27-9d36-450f63bc861c%2Fm3bcfzb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the data path below for a single cycle 32-bits MIPS processor
Assume that we are executing the following instruction
lw St1, 48($10)
What is the value of the element pointed by arrow number 1 by in hexadecimal?
Note that the PC and the content of registers $10 and $t1 are found in bottom left of the figure below
Data Memory
Select one
a. Ox00001724
Ob. 0x00002DE4
Oc 0x000016F4
Od 0x00001720
Oe. 0x00002DEO
Clear my choice
Rea
"
Address
Content
0x000016EC
0x0000ABOD
0x000016F0
0x00A01245
0x000016F4
0x00001A42
0x000171C
0x0008124F
0x0001720
0x00021345
0x0001724
0x000067AB
ALU
Ox0001734
0x0000AB35
0x0001738
0x0000FA72
0x0000ABOC
ALS
0x000174C
Register File and PC
$to = 0x000016FO
$t1 = 0x000016F4
PC = 0x0000148A0
(Before executing LW)
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