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Consider the constant pressure expansion that is illustrated in Figure beum. Initially the system contains 1 mole of gas A at 2 bar within a volume of 10 L. The expansion process is initiated by releasing the latch. The gas in the cylinder expands until the pressure of the gas matches the pressure of the surroundings. The final volume is 15.2 L. Calculate work done by the system during this process. ANS = -520J P= 1 bar P₁ = 2 bar V₁-10 L 1 mol gas A Initial state (1) Process Pg= 1 bar P₂= 1 bar V₂=15.2 L 1 mol gas A Final state (2)

Consider the constant pressure expansion that is illustrated in Figure beum. Initially the system contains 1 mole of gas A at 2 bar within a volume of 10 L. The expansion process is initiated by releasing the latch. The gas in the cylinder expands until the pressure of the gas matches the pressure of the surroundings. The final volume is 15.2 L. Calculate work done by the system during this process. ANS = -520J P= 1 bar P₁ = 2 bar V₁-10 L 1 mol gas A Initial state (1) Process Pg= 1 bar P₂= 1 bar V₂=15.2 L 1 mol gas A Final state (2)

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31 Consider the constant pressure expansion that is illustrated in Figure below. Initially the system contains 1 mole of gas A at 2 bar within a volume of 10 L. The expansion process is initiated by releasing the latch. The gas in the cylinder expands until the pressure of the gas matches the pressure of the surroundings. The final volume is 15.2 L. Calculate work done by the system during this process. ANS = -520J Pg= 1 bar P₁ = 2 bar V₁ = 10L 1 mol gas A Initial state (1) Process PE=1 bar P₂ = 1 bar V₂ = 15.2 L 1 mol gas A Final state (2)
Transcribed Image Text:31 Consider the constant pressure expansion that is illustrated in Figure below. Initially the system contains 1 mole of gas A at 2 bar within a volume of 10 L. The expansion process is initiated by releasing the latch. The gas in the cylinder expands until the pressure of the gas matches the pressure of the surroundings. The final volume is 15.2 L. Calculate work done by the system during this process. ANS = -520J Pg= 1 bar P₁ = 2 bar V₁ = 10L 1 mol gas A Initial state (1) Process PE=1 bar P₂ = 1 bar V₂ = 15.2 L 1 mol gas A Final state (2)
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