Consider the causal discrete-time LTI system described by the following constant coefficient difference equation: y(n) = 1.4y(n − 1) −0.48y(n − 2) + 2x(n − 1) + x(n − 2) - (a) Determine the system function H(z) and the impulse response h(n). Is the system BIBO stable? Is the system FIR or IIR? Is the system an-all pole system? (b) Suppose the system is initially relaxed, i.e., y(−1) = 0, y(−2) = 0, and the input x(n) = n()u(n) is applied to the relaxed system. Determine the zero-state response y(n). Deter- mine the system natural response Ynr (n) and the system forced response yfr(n). Simplify your answers as much as possible.

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Consider the causal discrete-time LTI system described by the following constant coefficient difference equation:

\[ y(n) = 1.4y(n - 1) - 0.48y(n - 2) + 2x(n - 1) + x(n - 2) \]

(a) Determine the system function \( H(z) \) and the impulse response \( h(n) \). Is the system BIBO stable? Is the system FIR or IIR? Is the system an all-pole system?

(b) Suppose the system is initially relaxed, i.e., \( y(-1) = 0, y(-2) = 0 \), and the input \( x(n) = n(\frac{1}{3})^n u(n) \) is applied to the relaxed system. Determine the zero-state response \( y(n) \). Determine the system natural response \( y_{nr}(n) \) and the system forced response \( y_{fr}(n) \). Simplify your answers as much as possible.
Transcribed Image Text:Consider the causal discrete-time LTI system described by the following constant coefficient difference equation: \[ y(n) = 1.4y(n - 1) - 0.48y(n - 2) + 2x(n - 1) + x(n - 2) \] (a) Determine the system function \( H(z) \) and the impulse response \( h(n) \). Is the system BIBO stable? Is the system FIR or IIR? Is the system an all-pole system? (b) Suppose the system is initially relaxed, i.e., \( y(-1) = 0, y(-2) = 0 \), and the input \( x(n) = n(\frac{1}{3})^n u(n) \) is applied to the relaxed system. Determine the zero-state response \( y(n) \). Determine the system natural response \( y_{nr}(n) \) and the system forced response \( y_{fr}(n) \). Simplify your answers as much as possible.
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