Consider the beam in (Figure 1). igure 200 lb 1.5 ft -2 ft 200 lb "C 1.25 ft <1 of 1 30 30 Determine the magnitude of F so that the resultant couple moment is 450 lb-ft, counterclockwise. Express your answer in pounds to three significant figures. F = [5] ΑΣΦ Submit Provide Feedback ↓↑ Request Answer vec ? lb

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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**Problem Statement**

Consider the beam in (Figure 1).

Determine the magnitude of \( F \) so that the resultant couple moment is 450 lb·ft, counterclockwise.

Express your answer in pounds to three significant figures.

\[ F = \quad \text{lb} \]

**Diagram Explanation**

The diagram shows a horizontal beam with a series of forces acting on it and their respective distances marked. Key points in the diagram include:

1. **Beam and Forces**: 
    - The beam is shown horizontally.
    - Two forces of 200 lb each are acting perpendicular to the beam. One force is located 2 feet from the left end, directed upwards. The other is located 1.5 feet from the right end, directed downwards.

2. **Force \( F \)**:
    - Two forces, each labeled \( F \), are acting at an angle of 30 degrees to the right end of the beam.
    - The point of application of \( F \) is 1.25 feet from the right end of the beam.

**Instructions for Students**

1. **Goal**: Calculate the magnitude of force \( F \) such that the resultant couple moment about the beam is 450 lb·ft acting counterclockwise.
2. **Precision**: Ensure your answer is rounded to three significant figures and expressed in pounds (lb).
3. **Submission**: Provide your calculated value in the text box and submit for evaluation. 

**Provide Feedback** to your solutions by using the provided link.
Transcribed Image Text:**Problem Statement** Consider the beam in (Figure 1). Determine the magnitude of \( F \) so that the resultant couple moment is 450 lb·ft, counterclockwise. Express your answer in pounds to three significant figures. \[ F = \quad \text{lb} \] **Diagram Explanation** The diagram shows a horizontal beam with a series of forces acting on it and their respective distances marked. Key points in the diagram include: 1. **Beam and Forces**: - The beam is shown horizontally. - Two forces of 200 lb each are acting perpendicular to the beam. One force is located 2 feet from the left end, directed upwards. The other is located 1.5 feet from the right end, directed downwards. 2. **Force \( F \)**: - Two forces, each labeled \( F \), are acting at an angle of 30 degrees to the right end of the beam. - The point of application of \( F \) is 1.25 feet from the right end of the beam. **Instructions for Students** 1. **Goal**: Calculate the magnitude of force \( F \) such that the resultant couple moment about the beam is 450 lb·ft acting counterclockwise. 2. **Precision**: Ensure your answer is rounded to three significant figures and expressed in pounds (lb). 3. **Submission**: Provide your calculated value in the text box and submit for evaluation. **Provide Feedback** to your solutions by using the provided link.
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