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Consider the adiabatic expansion of 0.05 moles of helium, a monatomic gas, from initial volume and temperature Vi = 0.1 m3, T; = 273.15 K, to V;= 2 m°. Use Equation 3.20 to calculate the work done. Confirm that this work value is the same as that obtained using Equation 3.25 Give your answer in units of joules (J).

= Cv{T; – T;} = CvAT
W =
(3.25)

p;V
P; V,
P;V"
(y – 1)
dV
1
1
W = -
(7 – 1)V-1
(3.20)
|
Vị
V-1
f

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