Consider projects X and Y below. If theMARR is 8%, what is the PW of X and Yrespectively, given a LCM life analysis?YFC-15,000 -28,000AOC-6,000-9,000Rebuild cost,-2000year 4SV3,0005,00048Group of answer choices-$56,679 and -$78,486-$53,806 and -$78,486-$51,757 and -$75,048-$51,757 and -$74,042

Given MARR = 8 % with LCM analysis the life of both the project is compared with same multiple of 8…

Answered: Consider projects X and Y below. If the…

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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I need help only with the second part of inputting this data into excel calculating the Annual Worth for both options. Then using Goal Seek to find out the new salvage value that will equal AW equations, thank you.
Time left 1:24:36 FW analysis comparison of alternatives is different from PW analysis. For example: Must compare alternatives for equal service. Select one: O a. False O b. True on Machines that have the following costs are under consideration for a robɔtized welding process. Using an interest rate of 10% per year, determine which alternative should be selected on the basis of a present worth analysis. Machine X Machine Y First Cost. S -250,000 -430.000 AOC. S per year -60.000 -40,000 Salvage Value. S 70,000 95.000 Life vears 3 Oa Select Machine X b. Select Machine Y O b. Select Machine Y Approximately, what is the value of (P) if A=380, n=11 years, and i= 10% per year? a. 2049 O b. 2468 C. 3308 O d. 2962
Consider two air-conditioning systems with the cash flow estimates as given below. Use AW analysis to determine the sensitivity of the economic decision to MARR values of 4%, 6%, and 8% per year. Air-Conditioning System 1 System First cost, $ AOC. $ per year Salvage valué, $ New compressor and motor cost at midlife, $ Life, years -9,000 -850 -100 Proy -2,200 8 The annual worth of air-conditioning system 1 when the MARR is 4% is $ The annual worth of air-conditioning system 2 when the MARR is 4% is $ The annual worth of air-conditioning system 1 when the MARR is 6% is $ The annual worth of air-conditioning system 2 when the MARR is 6% is $ 10 www Air-Conditioning System 2 -13,000 -105 -300 -3,140 12
5. The physical life is always greater than all the other "life" factors under replacement analysis. 6. If breakeven analysis is conducted with PW analysis for different MEAS, it doesn't guarantee that the fastest alternative to reach its breakeven point has also the highest equivalent worth.
A cost analysis is to be made to determine what, if anything, should be done in a situation offering three alternatives in addition to doing nothing. Costs and benefits of the alternatives are estimated as follows: Alternative Cost Uniform Annual Benefit Residual Value Useful life (years) A 450,000 150,000 0 4 B 550,000 125,000 300,000 4 с 800,000 135,000 250,000 8 Use an 8-year analysis period, "stacking" projects as necessary. Use Excel to choose which, if any, of the projects should be chosen: MÁRR is 15%. a. Using annual worth analysis b. Using rate of return analysis
I need the answer in 10 minutes please
Compare the alternatives C and D on the basis of a present worth analysis using an interest rate of 14% per year and a study period of 10 years. Alternative First Cost AOC, per Year Annual Increase in Operating Cost, per Year Salvage Value Life, Years с $-48,000 $-9,000 $-1,400 $8,000 10 The present worth of alternative C is $ -117974.14 Alternative D offers the lower present worth. D $-34,000 $-9,000 $-1,500 $1,400 5 and that of alternative D is $ -73129.34 x
Find the annual revenue
question 10 Based on the following cash flows and an interest rate of 10% per year Alternative X -300,000 -65,000 25,000 5 First cost, $ Annual cost, $/year Salvage value, $ Life, years -850,000 -10,000 160,000 % 00 1) What is the Annual Worth of Alternative X? $ 2) What is the Annual Worth of Alternative Y? $ 3) What is the annual worth of the first cost and salvage value for project X? $ 4) What is the annual worth of the first cost and salvage value for project Y? $ 5) What is the interest rate? 6) What is the project life for Alternative X? 7) What is the project life for Alternative Y? (Click to select)✓ years years
Three independent alternatives are given below. If MARR is 18%, what is your decision? A B C Initial Cost $4.50 $1.90 $1.20 Annual Revenues $4.00 $2.50 $3.00 Salvage Value $0.50 $0.90 $0.00 Annual Operating & Maintenance Costs $1.20 $1.90 $2.70 Estimated life, in years 3 Infinite
Question 3 For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10% Machine A Machine B Machine C First coșt, $ 22,356 30000 10000 Annual cost, $/year 8,673 6,000 4,000 Salvage value, S Life, years 4,000 5,000 1,000 Answer the below questions: A- AW for machine A= Selected Answer: O -24,525.26 Correct Answer: O -16,453 ± 19%

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Consider projects X and Y below. If the MARR is 8%, what is the PW of X and Y respectively, given a LCM life analysis? Y FC -15,000 -28,000 AOC -6,000 -9,000 Rebuild cost, -2000 уear 4 SV 3,000 5,000 4 8 Group of answer choices -$56,679 and -$78,486