Consider each of the following reactions and decide whether the standard entropy change for the reaction will be positive; or close to 0; or negative. Cu(s) + 2 H2SO4(aq) = CuSO4(aq) + 2 H20(1) + SO2(g) Mg(s) + CO2(g) = MgO(s) + CO(g) 1. negative BaSO4(s) + 2 H20(g) = BaSO4.2H2O(s) 2. positive 2 Na(1) + H2(g) = 2 NaH(s) 3. close to 0 NH3(g) + HCI(g) = NH4CI(s) CoH1206(s) + 6 O2(g) = 6 CO2(8) + 6 H2O(1) > > >
Consider each of the following reactions and decide whether the standard entropy change for the reaction will be positive; or close to 0; or negative. Cu(s) + 2 H2SO4(aq) = CuSO4(aq) + 2 H20(1) + SO2(g) Mg(s) + CO2(g) = MgO(s) + CO(g) 1. negative BaSO4(s) + 2 H20(g) = BaSO4.2H2O(s) 2. positive 2 Na(1) + H2(g) = 2 NaH(s) 3. close to 0 NH3(g) + HCI(g) = NH4CI(s) CoH1206(s) + 6 O2(g) = 6 CO2(8) + 6 H2O(1) > > >
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Consider each of the following reactions and decide whether the standard entropy
change for the reaction will be positive; or close to 0; or negative.
Cu(s) + 2 H2SO4(aq) =
CuSO4(aq) + 2 H2O(1) +
SO2(g)
Mg(s) + CO2(g) = MgO(s) +
CO(g)
1. negative
BaSO4(s) + 2 H20(g) =
BasO4.2H20(s)
2. positive
2 Na(1) + H2(g) = 2 NaH(s)
3. close to 0
NH3(g) + HCI(g) = NH4C(s)
C6H1206(s) + 6 O2(g) = 6
CO2(g) + 6 H20(1)
>
>
>](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9667b0a0-f675-48a8-b558-6f2dfa34e921%2F78c1768d-efa3-4965-9356-458dd56dc4e8%2Fzt29g7d_processed.png&w=3840&q=75)
Transcribed Image Text:Consider each of the following reactions and decide whether the standard entropy
change for the reaction will be positive; or close to 0; or negative.
Cu(s) + 2 H2SO4(aq) =
CuSO4(aq) + 2 H2O(1) +
SO2(g)
Mg(s) + CO2(g) = MgO(s) +
CO(g)
1. negative
BaSO4(s) + 2 H20(g) =
BasO4.2H20(s)
2. positive
2 Na(1) + H2(g) = 2 NaH(s)
3. close to 0
NH3(g) + HCI(g) = NH4C(s)
C6H1206(s) + 6 O2(g) = 6
CO2(g) + 6 H20(1)
>
>
>
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