Consider another ubiquitous probability-course urn containing well-mixed black and white balls. There are 15 balls in total, 5 white and 10 black. 3 are chosen, one at a time and at random. Let X; be 1 if the ith ball selected is white, and 0 otherwise. For parts (a) and (b), assume that the balls are selected without replacement. (a) Calculate the conditional probability mass function X1 given that X2 = 1. PX1 X2 (01) = PX1 X2 (1/1) 10 4 15 14 35 35 15 (b) Calculate the conditional probability mass function X1 given that X2 = 0. PX₁x2(0|0) = PX₁x₂ (10) = For parts (c) and (d), assume that the balls are selected with replacement. (c) Calculate the conditional probability mass function X1 given that X2 = 1. PX₁ X2 (01) PXX, (1/1)= (d) Calculate the conditional probability mass function X1 given that X2 = 0. PX₁x2(0/0) = PX₁ X2 (10) = Note: You can earn partial credit on this problem.

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Consider another ubiquitous probability-course urn containing well-mixed black and white balls. There are
15 balls in total, 5 white and 10 black. 3 are chosen, one at a time and at random. Let X; be 1 if the ith ball
selected is white, and 0 otherwise.
For parts (a) and (b), assume that the balls are selected without replacement.
(a) Calculate the conditional probability mass function X1 given that X2 = 1.
PX1 X2 (01) =
PX1 X2 (1/1)
10 4
15 14
35
35
15
(b) Calculate the conditional probability mass function X1 given that X2 = 0.
PX₁x2(0|0) =
PX₁x₂ (10) =
For parts (c) and (d), assume that the balls are selected with replacement.
(c) Calculate the conditional probability mass function X1 given that X2 = 1.
PX₁ X2 (01)
PXX, (1/1)=
(d) Calculate the conditional probability mass function X1 given that X2 = 0.
PX₁x2(0/0) =
PX₁ X2 (10)
=
Note: You can earn partial credit on this problem.
Transcribed Image Text:Consider another ubiquitous probability-course urn containing well-mixed black and white balls. There are 15 balls in total, 5 white and 10 black. 3 are chosen, one at a time and at random. Let X; be 1 if the ith ball selected is white, and 0 otherwise. For parts (a) and (b), assume that the balls are selected without replacement. (a) Calculate the conditional probability mass function X1 given that X2 = 1. PX1 X2 (01) = PX1 X2 (1/1) 10 4 15 14 35 35 15 (b) Calculate the conditional probability mass function X1 given that X2 = 0. PX₁x2(0|0) = PX₁x₂ (10) = For parts (c) and (d), assume that the balls are selected with replacement. (c) Calculate the conditional probability mass function X1 given that X2 = 1. PX₁ X2 (01) PXX, (1/1)= (d) Calculate the conditional probability mass function X1 given that X2 = 0. PX₁x2(0/0) = PX₁ X2 (10) = Note: You can earn partial credit on this problem.
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