Consider an RL circuit consisting of an inductor with an inductance of L henry(H)and a resistor with a resistance of R ohms (1) driven by a voltage of E(t) volts (V). Given the voltage drop across the resistor is ER = RI, and across the inductor is EL = L(dI / dt), Kirchhoff's Law gives Now suppose an RL circuit with a 202 resistor and a 0.04H inductor is driven by a constant voltage of 130V. If the initial resistor current is I(0) = 0A, find the current I and the voltages across the inductor EL and the resistorER in terms of time t. I(t) = = ER(t) EL(t) = dI L + RI = E(t) dt = A V V

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Consider an RL circuit consisting of an inductor with an inductance of  L henry (H) and a resistor with a resistance 
 of  R ohms  (Ω)driven by a voltage of  E(t)volts  (V).
Given the voltage drop across the resistor is  ER=RI , and across the inductor is  EL=L(dI/dt) , Kirchhoff's Law gives
Ld Idt+RI =E(t)
 
Now suppose an RL circuit with a  2Ω resistor and a  
0.04H inductor is driven by a constant voltage of  
130V . If the initial resistor current is  I(0)=0A , find the current  I and the voltages across the inductor EL and the resistor ER in terms of time  t.  

Find: I(t), ER(t),EL(t)

Consider an RL circuit consisting of an inductor with an inductance of L henry(H)and a
resistor with a resistance of R ohms (1) driven by a voltage of E(t) volts (V). Given
the voltage drop across the resistor is ER RI, and across the inductor is
EL = L(dI / dt), Kirchhoff's Law gives
I(t) =
Now suppose an RL circuit with a 20 resistor and a 0.04H inductor is driven by a
constant voltage of 130V. If the initial resistor current is I(0) = 0A, find the current I
and the voltages across the inductor EL and the resistorER in terms of time t.
=
ER(t)
=
EL(t):
=
-
dI
L- + RI = E(t)
dt
A
V
V
Transcribed Image Text:Consider an RL circuit consisting of an inductor with an inductance of L henry(H)and a resistor with a resistance of R ohms (1) driven by a voltage of E(t) volts (V). Given the voltage drop across the resistor is ER RI, and across the inductor is EL = L(dI / dt), Kirchhoff's Law gives I(t) = Now suppose an RL circuit with a 20 resistor and a 0.04H inductor is driven by a constant voltage of 130V. If the initial resistor current is I(0) = 0A, find the current I and the voltages across the inductor EL and the resistorER in terms of time t. = ER(t) = EL(t): = - dI L- + RI = E(t) dt A V V
Expert Solution
Step 1: Introduction of the given problem

L fraction numerator d I over denominator d t end fraction plus R I equals E open parentheses t close parentheses
I open parentheses 0 close parentheses equals 0
R equals 2 space capital omega
L equals 0.04 space H
E open parentheses t close parentheses equals 130

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